Solve for X. what is (x-48)+(2x-164)

The value of the numerator of a particular fraction is one-half the value of its denominator. If the numerator is increased by 2

IgorC [24]

Answer:

14

Step-by-step explanation:

Let the original denominator be 2x.

The original numerator is x.

The original fraction is x/(2x).

The numerator is increased by 2, and the denominator is decreased by 2.

The new fraction is (x + 2)/(2x - 2).

The new fraction equals 3/4.

(x + 2)/(2x - 2) = 3/4

Cross multiply.

4(x + 2) = 3(2x - 2)

4x + 8 = 6x - 6

-2x = -14

x = 7

The original numerator was 7.

2x = 2(7) = 14

The original denominator was 14.

8 0

3 years ago

FREE POINTS!!!!

algol13

Answer:

a ≈

2.594

b ≈

2.705

c ≈

2.718

d ≈

2.718

e ≈

2.718

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A certain company has a fixed cost of $200 per day. It costs the company $3.10 per unit to make its products. The company is

Alex17521 [72]

Answer:

a. The horizontal asymptote of y = 3.10 represents that the average cost per unit will approach $3.10 as the number of units produced increases.

Step-by-step explanation:

A certain company has a fixed cost of $200 per day. Then it costs the company $3.10 per unit to make its products.

So, the total cost will be,

Then average cost f(x) will be,

As this an equation of hyperbola (rectangular hyperbola).

Its vertical asymptote is (equating denominator to zero),

i.e y axis.

Its horizontal asymptote is (leading coefficient of numerator divided by leading coefficient of denominator),

As x approaches infinity, f(x) approaches 3.10.

Therefore, option a is correct.

3 0

4 years ago

Read 2 more answers

The product of two integers is 112. One number is four more than three times the other. Which of the following equations could b

shepuryov [24]

Answer:

The equations could be used to find one of the numbers is, $3a^2 + 4a =112$

Step-by-step explanation

Let two integers be a and b.

As per the given statement:

The product of two integers is 112.

⇒ $ab =112$ ......[1]

Also, One number is 4 more than three times the other.

⇒b = 3a +4 ......[2]

Now substitute equation [1] in [2] we get

$a(3a+4) =112$

Using distributive property i.e, $a \cdot (b+c) = a\cdot b + a\cdot c$

$(a)(3a)+ 4a = 112$

Simplify:

$3a^2 + 4a =112$

therefore, the equation that could be used to find one of the numbers is;

$3a^2 + 4a =112$

4 0

3 years ago

Write an equivalent expression for the 4th root of 324m^12 * the cubed root of 64k^9. Need help!

Elis [28]

Answer:

The equivalent expression to the givan expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Step-by-step explanation:

Given expression is 4th root of 324m^12 * the cubed root of 64k^9

The given expression can be written as

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

To find the equivalent expression to the given expression :

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

$=\sqrt[4]{81\times 4m^{12}}\times\sqrt[3]{16\times 4k^9}$

$=\sqrt[4]{3\times 3\times 3\times 3\times 4m^{12}}\times\sqrt[3]{4\times 4\times 4k^9}$

$=(3\times \sqrt[4]{m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4}\times (m^{12})^{\frac{1}{4}})\times (4\times {(k^9)^{\frac{1}{3}})$

$=(3\sqrt[4]{4}\times m^{\frac{12}{4}})\times (4\times k^{\frac{9}{3}})$

$=(3\sqrt[4]{4}\times m^3)\times (4\times k^3)$

$=3\sqrt[4]{4}m^3.4k^3$

$=12\sqrt[4]{4}m^3k^3$

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Therefore the equivalent expression to the given expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

8 0

3 years ago