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Tomtit [17]
3 years ago
13

During the first race, 13 people ran a 1.5 mile race. During the second race, 5 people ran a 2.2 mile race. How many more total

miles did the competitors run during the first race compared to the second race?
Mathematics
1 answer:
OLga [1]3 years ago
4 0

Answer:

8.5

Step-by-step explanation:

The competitors in the first race ran 19.5 miles and the competitors in the second race ran 11.

I hope this helps and makes sense! :)

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Use lagrange multipliers to find the points on the cone z2 = x2 + y2 that are closest to (16, 6, 0).
Inga [223]
Minimize (x-16)^2+(y-6)^2+z^2 subject to z^2=x^2+y^2. The Lagrangian would be

L(x,y,z,\lambda)=(x-16)^2+(y-6)+z^2+\lambda(z^2-x^2-y^2)

and has partial derivatives

\begin{cases}L_x=2(x-16)-2\lambda x\\L_y=2(y-6)-2\lambda y\\L_z=2z+2\lambda z\\L_\lambda z^2-x^2-y^2\end{cases}

Setting each partial derivative to 0, we have

\begin{cases}2(x-16)-2\lambda x=0\implies (1-\lambda)x=16\\2(y-6)-2\lambda y=0\implies(1-\lambda)y=6\\2z+2\lambda z=0\implies(1+\lambda)z=0\\z^2-x^2-y^2=0\implies z^2=x^2+y^2\end{cases}

From the third equation, it follows that either \lambda=-1 or z=0. In the second case, we arrive at a contradiction:

z^2=x^2+y^2=0\implies x=y=0

since both x^2 and y^2 must be non-negative, yet this would mean e.g. (1-\lambda)x=0=16. So it must be that \lambda=-1.

The first and second equations then tell us that

(1-\lambda)x=2x=16\implies x=8
(1-\lambda)y=2y=6\implies y=3

from which we obtain z^2=8^2+3^2=73\implies z=\pm\sqrt{73}.

Thus the points on the cone closest to (16, 6, 0) are (8,3,\pm\sqrt{73}).
4 0
3 years ago
GIYS HELP ASAP!!! i need to find the average
Korvikt [17]

Answer:

average grade = 90%

Step-by-step explanation:

to find the average: add all the grade points up and divide it by the # of grades listed (in this case, 5)

100 + 95 + 75 + 100 + 80 = 450

450/5 = 90

average grade = 90%

6 0
3 years ago
Read 2 more answers
Find the period of an electromagnetic wave of wavelength 2.20 × 10–2 m. A. 1.36 × 1010 s c. 7.33 × 10–11 s b. 4.54 × 101 s d. 6.
vovangra [49]

Answer:

7.33 * 10^-11 s

Step-by-step explanation:

Period, T = 1 / f

c = fλ

λ = 2.20 × 10^–2 m

c = speed of light = 3 * 10^8 m

f = c / λ

f = 3 * 10^8 ÷ 2.20 × 10^–2 m

f = (3/2.2) * 10^(8-(-2))

f = 1.364 * 10^10

T = 1/f

T = 1 / 1.364 * 10^10

T = 7.33 * 10^-11 s

4 0
3 years ago
Solve the equation for d. 0.2(d-6)=0.3d+5-3+0.1d
maria [59]

Answer:

Step-by-step explanation:

0.2(d - 6) = 0.3d + 5 - 3 + 0.1d

0.2d - 1.2 = 0.4d + 2

     - 0.2d = 3.2

           d = - 16

7 0
2 years ago
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How is finding the factors of a number different from finding the prime factorization of a number
ICE Princess25 [194]
Cause a prime number is a number that can only be divideed by itself like 19
factors are 0 2 4 6 8 10
8 0
3 years ago
Read 2 more answers
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