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Alexeev081 [22]
3 years ago
8

Find a42 if a40=9, a41=36

Mathematics
2 answers:
ZanzabumX [31]3 years ago
6 0
9 x 4 = 36

36 x 4 = 144

42 = 144

Guessing.
UNO [17]3 years ago
5 0
Sisjsjsjdjsjsksksjskssjjs
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What is the solution to the following system
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C is the answer.............

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Y - (-9) = 8?<br><br> I am confused
Yuki888 [10]

Answer:

y = -1

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y - ( - 9) = 8

y + 9 = 8

y = 8 - 9

y = -1

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Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0
Masja [62]

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

h(x)=\dfrac{1}{3}|x-6|+4

Put the values of x to the equation of the function h(x):

x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6


6 0
2 years ago
Plz help me on 8 question
Salsk061 [2.6K]
No they are not at $3 for 6 bagles for $9 you only get 18 BAGLES
8 0
3 years ago
-14,-10,_,-2,2,6 missing sequence
OLga [1]

-14,-10,-6,-2,2,6

Answer by Mimiwhatsup: I could easily subtract -14 from -10 to find out the sequence so they are adding four each time. That means the pattern will continue going on like this 10, 14, 18, 22 and so forth.

6 0
3 years ago
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