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Ahat [919]
3 years ago
9

How do I make this bell curve

Mathematics
1 answer:
Zanzabum3 years ago
8 0

The mean you found is correct, but the standard deviation is not. Recall that the standard deviation \sigma_s (s for sample) of n points is given by

\sigma_s=\sqrt{\dfrac1{n-1}\displaystyle\sum_{1\le i\le n}(x_i-\bar x)^2}

where n=10 is the sample size, \bar x=3740 is the sample mean, and x_i are the prices listed in the circled column. So

\sigma_s=\sqrt{\dfrac{(3640-3740)^2+(7595-3740)^2+\cdots+(3390-3740)^2}{10-1}}

\implies\sigma_s\approx1443.98\approx1444

I can't tell if you need to provide any more info beyond this, but given there's a plot of a generalized bell curve, I think you're also supposed to label the plot.

At the center of the bell-shaped/normal distribution is the mean. Notice there are three tick marks to either side of the mean - these are probably supposed to represent prices that fall exactly 1, 2, and 3 standard deviations from the mean. These are, from left to right,

\bar x-3\sigma_s\approx3740-3(1444)=-592

\bar x-2\sigma_s\approx3740-2(1444)=852

\bar x-\sigma_s\approx2296

\bar x+\sigma_s\approx5184

\bar x+2\sigma_s\approx6628

\bar x+3\sigma_s\approx8072

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Answer:

Pr = 0.059049

Step-by-step explanation:

Given

p = 0.9 --- probability of scoring

Required

Probability that his first miss is his 6th shot

Let q represent the event that he did not score.

Using complement rule:

q = 1 - p = 1 - 0.9 = 0.1

The event that his first miss is his 6th is represented as:

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So, the probability is:

Pr = p^5 * q

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Pr = 0.059049

7 0
3 years ago
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7 0
3 years ago
What is the approximate curcumfrance of the circle shown below?​
Vikki [24]

Answer:

C.

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Circumference=PI*diameter

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3 0
3 years ago
PLS SOLVE ASAP!!!
cupoosta [38]
180 + 30x = 60 + 50x
⇒ 20x = 120
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3 0
3 years ago
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Answer:

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7 0
3 years ago
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