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Hunter-Best [27]
3 years ago
14

What is the measure of the missing angle? 56, 36, ?

Mathematics
1 answer:
tia_tia [17]3 years ago
8 0
56+36=92
180-92=88
The missing angle is 88 degrees
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The sum of 3 consecutive even integers is 78. What is the largest of the integers?
Maksim231197 [3]

Answer:

is the sum 78 or 7,878 (i.e. was there a stutter)?

In any event, this sum must be even, so 3 consecutive even integers would be n, n+2 & n+4 whose sum is 3n + 6.

Set that to either 78 or 7878, whichever is intended, & solve for n.   If 78 is their grand total, then those 3 consecutive even numbers have to be 24, 26 & 28.

No stress!  Just logic! Keep the faith!

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
How would I solve this?
zvonat [6]
Use Pythagorean Theorem which states that in a right triangle:

 a^2+b^2=c^2, where a and b are the legs, and c is the hypotenuse.

24^2+10^2=x^2

Take the square root of both sides to solve for x.

x =  \sqrt{676} = 26

The answer  is 26.


4 0
3 years ago
The distance from the Earth to the moon is about 239,000 miles. Rewrite the distance in scientific notation.
egoroff_w [7]

Answer:

2.39 x 10^5 miles

Step-by-step explanation:

Although it is not usually written, there is always a .0 at the end of a number unless there is a specific decimal that was given.

So, the number here is 239,000.0 and if you count the number of spaces that the decimal needs to move in order to be in the correct spot for scientific notation (which is always after the first number), there is 5 spaces.

Therefore the answer is 2.39 x 10^5 miles.

4 0
1 year ago
What is the solution to the proportion 3/5=x/10
Savatey [412]
x is 6.

3 / 5 = 6 / 10

Where 10 / 5 = 2 then 2 * 3 = 6.

6 / 10 simplified by dividing both numerator and denominator by 2 will result to 3 / 5.
7 0
3 years ago
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At the beginning of year 1, Sam invests $700 at an annual compound interest
Aleksandr-060686 [28]

at the beginning of year 4, only 3 years have elapsed, the 4th year hasn't started yet, since it's at the beginning, so at the beginning of year 4 we can say only 4-1 years have elapsed.

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$700\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=\textit{elapsed years}\dotfill &3 \end{cases}

A=700\left( 1 + \frac{0.05}{1} \right)^{1\cdot 3}\implies A = 700(1+0.05)^3\implies A(4)=700(1+0.05)^{4-1} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill A(n)=700(1+0.05)^{n-1}~\hfill

6 0
2 years ago
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