The probability that 5 would not be working is 0.18665, the probability that at least one machine would be working is 0.00602 and the probability that all would be working is 1.

Given a company has 200 machines. Each machine has a 12% probability of not working.

If we working pick 40 machines randomly then we have to find the probability that 5 would not be working, the probability that at least one machine would be working, and the probability that all would be working.

1) probability that 5 would not be working

C(40,5)·0.12⁵·0.88³⁵= 40!/(5!(40-5)!)·0.12⁵·0.88³⁵

≈ 0.18665

2) probability that at least one machine would be working

0.88⁴⁰ ≈ 0.00602

3) probability that all would be working

1 - 0.12⁴⁰ ≈ 1.0000

Learn more about probability here: brainly.com/question/24756209

#SPJ10

7 0

1 year ago

Suppose a country has a population of 50 million and projects a growth rate of 4% per year for the next 20 years. What will the

ser-zykov [4K]

Answer:

The population of this country in 11 years will be 76972702.82

Step-by-step explanation:

The population of this country in 11 years can be calculated using the formula

Population in 11 years = Starting population x $(1+growth rate)^{period}$

Thus

Population in 11 years =50000000× $(1+0.04)^{11}$ =76972702.82

6 0

2 years ago

Solve for x. Round to the nearest tenth, if necessary.

Nina [5.8K]

Answer:

15.4 (rounded to 1dp)

Step-by-step explanation:

5 0

2 years ago