Question

Please help

Answer 1

Answer:

The missing value in last step is 3

Step-by-step explanation:

Given the function f(x)

$f(x)=18x+3x^2$

Here some steps are given to write the above function in vertex form.

Step 1: Factor a out of the first two terms

$f(x)=3(x^2+6x)$

Step 2: Form a perfect square trinomial.

$f(x) = 3(x^2 + 6x + 9) - 3(9)$

Write the trinomial as a binomial squared.

By the identity of binomial square

$a^2+2ab+b^2=(a+b)^2$

$x^2 + 6x + 9=x^2+2(x)(3)+3^2$

$\text{Put a=x and b=3 in the identity, we get}$

$x^2+2(x)(3)+3^2=(x+3)^2$

$x^2 + 6x + 9=(x+3)^2$

Hence, the f(x) can be written as

$f(x) = 3(x+3)^2 - 3(9)$

Therefore, the missing value in last step is 3

Answer 2

3 is the missing value

Of there is any more help needed I can give you more tips and notes