Question

SI on rs 5000 at 10percent for a certain period is rs 500 less then the interest on rs 6000 at 10 percent p.A for the same period of time . Find time

Answer 1

Answer:

The time period was of 5 years.

Step-by-step explanation:

The formula to compute the simple interest is:

$SI=\frac{P\times r\times t}{100}$

The information provided is as follows:

$P_{1}=5000\\\\r_{1}=10\%\\\\P_{2}=6000\\\\r_{2}=10\%\\\\SI_{1}=S_{2}-500$

The time period is same for both the amounts.

Compute the time t as follows:

                           $SI_{1}=SI_{2}-500$

                 $SI_{2}-SI_{1}=500$

    $\frac{P_{1}\times r_{1}\times t}{100}-\frac{P_{2}\times r_{2}\times t}{100}=500$

$\frac{6000\times 10\times t}{100}-\frac{5000\times 10\times t}{100}=500$

               $600t-500t=500$

                          $100t=500$

                               $t=5\ \text{years}$

Thus, the time period was of 5 years.