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Dimas [21]
3 years ago
8

WILL GIVE BRAINLIEST AND 30 POINTS! Peter calculated |5 + 13i| by finding Where was Petey’s mistake? He should not have used the

Pythagorean theorem. He should have used 13 instead of 13i. (13i)2 = 169, not –169.

Mathematics
2 answers:
tiny-mole [99]3 years ago
5 0

Answer: He should have used 13 instead of 13i

Step-by-step explanation:

katen-ka-za [31]3 years ago
4 0

The next answer on Edge is approximately 8.6

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The quotient of 12 and the product of 5 and t
n200080 [17]

The quotient of 12 and the product of 5 and t is:

\frac{12}{5t}

4 0
4 years ago
A group of 55 students and five chaperones is going on a field trip. The buses can hold 25 people. How many buses will this grou
stepan [7]

Answer:

3 Buses

Step-by-step explanation:

55 students and 5 chaperones

one bus holds 25

2 buses would hold 50

need one more bus for remaining 5 students and 5 chaperones

therefore the group will need 3 Buses

5 0
3 years ago
Can anyone answer this for me?
Genrish500 [490]

Answer:

x\geq 5

Step-by-step explanation:

6 0
3 years ago
You spin a spinner with 4 sections 1 yellow (y) , 1 purple (p) 1 red (r) and 1 blue (b) which is the sample space for one spin o
Ira Lisetskai [31]

Answer:

<h2>{Y,P,R,B}</h2>

Step-by-step explanation:

apex said it was right

<3

3 0
3 years ago
Read 2 more answers
A frog sits at one end of a table which is 2m long. In its first jump the frog goes a distance of 1m along the table, with its s
Phantasy [73]
Ah, this is an infinite sum question, or a sum of geometric sequence
when will the sum reach 1cm of the edge or about 1.99m
so

2m=200cm
within 1cm means at least 1.99m
so
we will use m and not cm for consitancy

sum of geometric sequence is
S_n= \frac{a_1(1-r^n)}{1-r}
a1=first term=initial jjump=1
r=common ratio=1/2
n=?, we ar solving for that

so
we want it to equal 1.99 so

1.99= \frac{1(1- (\frac{1}{2})^n)}{1-\frac{1}{2}}
1.99= \frac{(1- (\frac{1}{2})^n)}{\frac{1}{2}}
1.99= 2(1- (\frac{1}{2})^n)
divide both sides by 2
\frac{1.99}{2} = 1- (\frac{1}{2})^n
times -1
\frac{-1.99}{2} = (\frac{1}{2})^n-1
add 1 or 2/2 to both sides
\frac{0.01}{2} = (\frac{1}{2})^n
take the ln of both sides
ln(\frac{0.01}{2}) = ln((\frac{1}{2})^n)
ln(\frac{0.01}{2}) = n ln(\frac{1}{2})
divide both sides by ln(1/2)
\frac{ln(\frac{0.01}{2})}{ln(\frac{1}{2})} =n
use your calculatro to find that n≈7.64386
so on 7th jump, it is not yet at 1cm to the edge but at 8th jump, it is past
so 8th jump
7 0
4 years ago
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