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LiRa [457]
3 years ago
6

A hairstylist schedules 1/4 our trim a customer's hair and 1/6 hour to style the customers hair hairstyles plans to work 3 1/3 h

ours each day for five days a week how many appointments can hairstylist schedule each week if the customer must be trimmed and styled A hairstylist schedules 1/4 hour trim a customers hair and 16 away to style the customers here he said his plans to work 3 1/3 hours each day for five days a week how many appointments can hairstylist schedule each week if the customer must be trained in styl
Mathematics
1 answer:
aliina [53]3 years ago
6 0

Answer:

40 appointments

Step-by-step explanation:

From the question, we have the following information

Amount of time to trim a customer's hair = 1/4 hour

Amount of time to style a customer's hair = 1/6 hour.

Total time spent on a customer

= (1/4 + 1/6)hour

L.C.M = 12

= (3 + 2/12) = 5/12 hour spent on a customer for trimming and styling

She plans to work for 3 1/3 hours per day for 5 days a week.

The total number of hours in a week that she works is calculated as:

3 1/3 × 5

= 10/3 × 5 = 50/3 hours = 23 1/3 hours

1 customer = 1 appointment = 5/12 hour

Therefore, the number of appointments she can schedule for 5 days a week if the customer must trim and style is calculated as:

5/6 hour = 1 appointment

50/3 hours = x appointments

Cross Multiply

5/6 hour × x = 50/3 hour × 1 appointment

x = 50/3 ÷ 5/12

x = 50/3 × 12/5

= 40 appointments.

The number of appointments she can schedule for 5 days a week if the customer must trim and style is 40 appointments.

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<u>Answer</u>:

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HELLOOOO HELP PLEASE
MA_775_DIABLO [31]

Answer:

2*log(x)+log(y)

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

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   So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: log_ba=x\implies b^x=a

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    We get the equation: b^{xc}=a^c

    If we convert this back into logarithmic form we get: log_ba^c=x*c

    Since x was the basic logarithm we started with, we substitute it back in, to get the equation: log_ba^c=c*log_ba

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

    log_b{ac}=log_ba+log_bc

    Now for a quick proof, let's just say: x=log_ba\text{ and }y=log_bc

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Now let's use these identities to rewrite the equation you gave

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Now using the logarithm of a power to rewrite the log(x^2) we get:

2*log(x)+log(y)

3 0
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Assoli18 [71]

Answer:

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Step-by-step explanation:

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