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LiRa [457]
4 years ago
6

A hairstylist schedules 1/4 our trim a customer's hair and 1/6 hour to style the customers hair hairstyles plans to work 3 1/3 h

ours each day for five days a week how many appointments can hairstylist schedule each week if the customer must be trimmed and styled A hairstylist schedules 1/4 hour trim a customers hair and 16 away to style the customers here he said his plans to work 3 1/3 hours each day for five days a week how many appointments can hairstylist schedule each week if the customer must be trained in styl
Mathematics
1 answer:
aliina [53]4 years ago
6 0

Answer:

40 appointments

Step-by-step explanation:

From the question, we have the following information

Amount of time to trim a customer's hair = 1/4 hour

Amount of time to style a customer's hair = 1/6 hour.

Total time spent on a customer

= (1/4 + 1/6)hour

L.C.M = 12

= (3 + 2/12) = 5/12 hour spent on a customer for trimming and styling

She plans to work for 3 1/3 hours per day for 5 days a week.

The total number of hours in a week that she works is calculated as:

3 1/3 × 5

= 10/3 × 5 = 50/3 hours = 23 1/3 hours

1 customer = 1 appointment = 5/12 hour

Therefore, the number of appointments she can schedule for 5 days a week if the customer must trim and style is calculated as:

5/6 hour = 1 appointment

50/3 hours = x appointments

Cross Multiply

5/6 hour × x = 50/3 hour × 1 appointment

x = 50/3 ÷ 5/12

x = 50/3 × 12/5

= 40 appointments.

The number of appointments she can schedule for 5 days a week if the customer must trim and style is 40 appointments.

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5510 = x + (x + 100) + (x + 200) + (x + 300) + (x + 400) + (x + 500) + (x + 600) + (x +700) + (x + 800) + (x + 900) = 10x + 4500

=> 10x = 5510 - 4500 = 1010

=> x = 1010 / 10 = 101

=> least prize = 101 and greatest prize = 101+ 900 = 1001.<----- answer




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3 years ago
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Answer:

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Step-by-step explanation:

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A town planner wants to build two new streets, Elm Street and Garden Road, to connect parallel streets Maple Drive and Pine Aven
Advocard [28]

Answer:

72°

Step-by-step explanation:

From the information given:

A town planner wants to build two new streets, Elm Street and Garden Road, to connect parallel streets Maple Drive and Pine Avenue.

We are also told that there is a  Trapezoid EFGH with EH as the Pine avenue and EF as the Elm street.

However, side FG and EH are parallel.

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From the property of parallel lines :

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