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docker41 [41]
3 years ago
10

You want to accumulate $1 million by your retirement date, which is 25 years from now. You will make 25 deposits in your bank, w

ith the first occurring today. The bank pays 7% interest, compounded annually. You expect to receive annual raise of 3%, which will offset inflation, and you will let the amount you deposit each year also grow by 3% (i.e., your second deposit will be 3% greater than your first, the third will be 3% greater than the second, etc.). How much must your first deposit be if you are to meet your goal
Business
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

First deposit will be $11,213.87

Explanation:

To derive how much the first deposit must be, the deposit can be derived by using payment formula for growing annuity

P = FV x (r - g) / [(1 + r)^n - (1 + g)^n]

When FV = $1,000,000

r = 7%

g = 3%

n = 25

Hence, First payment will be:

P = 1,000,000 * (7% - 3%) / (1.07^25 - 1.03^25)

P = 1,000,000 * 4% / 5.427433 - 2.093778

P = 40,000 / 3.333655

P = 11998.842

P = $11,998.84

However, this formula is applicable when the payments are made at the end of the year. In this case the payments are upfront, occurring today. We need to adjust this first payment to reflect the early payment.

Hence, first payment = $11,998.84  / (1 + 7%)

First payment =  $11,998.84  / (1 + 0.07)

First payment = $11,998.84  / 1.07

First payment = 11213.8691588785

First payment = $11,213.87

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Answer:

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Explanation:

4 0
2 years ago
Read 2 more answers
Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

4 0
3 years ago
Your birthday is next week and instead of other presents, your parents promised to give you $2,200 in cash. Since you have a par
vfiekz [6]

Answer:

Interest revenue from the CD 470.04

Explanation:

we will calcualte the future value of the CD and from there calculate the interest:

Principal \: (1+ r)^{time} = Amount

Principal 2,200.00

time 8.00 (2 years x 4 quarter per year)

rate 0.02450 (9.8% divided by 4 quarter per year)

This divisions and multiplication are done to make time and rate be express i nthe same metric.

2200 \: (1+ 0.0245)^{8} = Amount

Amount 2,670.04

Now, we calculate interest revenue:

Amount - Principal

2,670.04 - 2,200 = 470.04

3 0
3 years ago
The optimal solution to a linear programming model that has been solved using the graphical approach:______.
wlad13 [49]

Answer:

Option d would be the appropriate choice.

Explanation:

  • At either the vertices including its continuum that ranges exist the optimal solutions towards linear programming challenges. Throughout this instance, the feasible area is just the section between some of the blue as well as red sections of the green map.
  • The green squares that describe the point of convergence between some of the red or green outlines seem to be the optimal solution.

Some other choices don't apply to the specified situation. So, the best one is the one mentioned.

5 0
3 years ago
Gary’s Company produces high quality shirts. Shirts must be well made because of frequent washings. Currently, Gary sells 10,000
grin007 [14]

Answer:

Unless the capacity is expanded or some of the production gets outsource, the offer is not convenient.

Explanation:

Giving the following information:

Currently, Gary sells 10,000 shirts at $60 each with the capacity to produce 11,000 shirts. Gary is considering a special order for 1,800 shirts for $40.

Gary has the following costs:

Unit Costs $200,000

Facility Costs $140,000

If Gary accepts the special order, they will incur an additional $2 per shirt in foreign currency transaction costs.

Because it is a special offer and there is unused capacity, we will not have into account the fixed costs.

variable cost per unit= (200,000/10,000) + 2= $22

Effect on income= (40 - 22)*1,800= $32,400

We have to take into account the loss of not selling 1,000 units.

Effect on income= 1,000*40= $40,000

Total effect= 32,400 - 40,000= $7,600

Unless the capacity is expanded or some of the production gets outsource, the offer is not convenient.

6 0
3 years ago
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