Answer:
Step-by-step explanation:
Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m
Dimensions of a small locker are 0.5 m × 0.6 m × 
(as height of small locker is half the height of big locker )
To find: total volume of one big locker and one small locker
Solution:
Volume of cuboid = length × breadth × height
Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker
= 
Answer:
A) 5x-7y=58
B) y=-x+2 we rearrange B) into
B) x + y = 2 then we multiply B) by -5
B) -5x -5y = -10 adding this to A)
A) 5x -7y = 58 we get
-12y = 48
y = -4
B) x + y = 2
x = 2 +4
x = 6
Step-by-step explanation:
I believe the answer would be Z < (Z+5)
Let the shortest side be = a, then side b = 2·a and side c = (b + 24)
We are given that a + b + c = 84
Substituting for b and c
a + 2·a + (a + 24) = 84
4·a + 24 = 84
4·a = 84 - 24 = 60
a = 60/4 = 15 feet
b = 2·15 = 30 feet
c = 15 + 24 = 39 feet
sorry if i am wrong
Answer:
-242
Step-by-step explanation:
I am Cermet
