The value of f⁻¹(f(58)) is 58 and the value of the function f(f(5)) is 11
<h3>How to solve the function values?</h3>
As a general rule, we have:
f⁻¹(f(x)) = x
Substitute 58 for x
So, we have:
f⁻¹(f(58)) = 58
Hence, the value of f⁻¹(f(58)) is 58
Also, we have:
f(f(5))
From the table, we have:
f(5) = 9
So, we have:
f(f(5)) = f(9)
From the table, we have:
f(9) = 11
So, we have:
f(f(5)) = 11
Hence, the value of the function f(f(5)) is 11
Read more about invertible function at:
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Answer:
0=0
Step-by-step explanation:
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:
(x-4)=0 ===> x=4,
so that now you have to plot 2 functions!
For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:
|x-4| = -(x-4)=4-x
Then:
for x<=4, y = -x+4-7 = -x-3
for x=>4, (x-4) is positive, so no changes:
y= x-4-7 = x-11,
Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11
In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:
x=4 and x= 3 for y=-x-3
And just x=5 for y=x-11
The reason is that the absolute value is continuous, so x=4 works for both:
x=4===> y=-4-3 = -7
x==4 ====> y = 4-11=-7!
abs() usually have a cusp int he point where it is =0
Hope it helps, despite being this long!
Y= 5, 2, 1, 2,5
............
Answer:
B, C, D
Step-by-step explanation:
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