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timama [110]
3 years ago
5

I need help to find the answer

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
8 0
Last year they gave 80% to school which was 3200$
and 20%  amount to fund raiser which was  800$
total was 4000$

With the same assumption if this year also they want to give 80% to the school which is 4000 this year

80% of X=4000
x=5000$

total they need to earn this is year is 5000$ so they can give 4000$ to the school.

A) They need to earn 1000$ more to earn before paying the cost.

B)This is they need to earn 5000$

2) DJ KAy Cee charges 150 $ per hr
DJ Fab Fred charges 180$ per hrs

so for some hrs they both will cost same charges
lets say x is charges for DJ kay and y is cost for DJ Fred

150*x=180*y
150/180=x/y
5/6=x/y

6x=5y
means DJ key will charge the same if he work for 6 hr to the DJ fred if he worked 5 hrs





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Answer:

The linear equation is y = 6 x + 9

The graph is attached down

Step-by-step explanation:

The given information:

The cost of 1st km is 9 Rs

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Solve 2x^2 + x - 4 = 0 <br> X2 +
damaskus [11]

Answer:

\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }

Step-by-step explanation:

Hello, please find below my work.

2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0

\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}

Hope this helps.

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