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timama [110]
3 years ago
5

I need help to find the answer

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
8 0
Last year they gave 80% to school which was 3200$
and 20%  amount to fund raiser which was  800$
total was 4000$

With the same assumption if this year also they want to give 80% to the school which is 4000 this year

80% of X=4000
x=5000$

total they need to earn this is year is 5000$ so they can give 4000$ to the school.

A) They need to earn 1000$ more to earn before paying the cost.

B)This is they need to earn 5000$

2) DJ KAy Cee charges 150 $ per hr
DJ Fab Fred charges 180$ per hrs

so for some hrs they both will cost same charges
lets say x is charges for DJ kay and y is cost for DJ Fred

150*x=180*y
150/180=x/y
5/6=x/y

6x=5y
means DJ key will charge the same if he work for 6 hr to the DJ fred if he worked 5 hrs





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the area of a parallelogram is 36x^6y^5. if the base of the parallelogram is 3xy^2,what is the height of the parallelogram ​asap
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The area of a parallelogram is found using A = b*h. Substitute the values given and solve for h.

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Determine the midpoint between the points (-5, 3) and (5, 9).
PSYCHO15rus [73]

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M (0, 6)

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M [-5+5/2 , 3+9/2]

M (0/2 , 12/2)

M (0, 6)

4 0
2 years ago
A box contains 2 plain pencils and 2 pens. A second box contains 3 color pencils and 5 crayons. One item from each box is chosen
Lapatulllka [165]

Answer:

50% pen first box and 62.5% crayon from second box

Step-by-step explanation:

The first box contains 4 items, 2 of each. This means there are \frac{2}{4} pens. This gives you a \frac{2}{4} chance of picking out a pen. This can be written as 50%.

The second box contains 8 items, 3 color pencils and 5 crayons. This means \frac{5}{8} of the contents are crayons, meaning you have a \frac{5}{8} or 62.5% chance of picking a crayon.

*For working out the percentages, you should convert the fraction to a decimal and then multiply that by 100.

**This content involves fractions, decimals and percentages, as well as basic probability, which you may want to revise. I'm always happy to help!

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