One tenth the value of 2 in 8.524

5.

mariarad [96]

Answer:

MARK AS BRAINLIEST

4 0

3 years ago

Suppose a manufacturer finds that 95% of their production is normal but the final 5% has one or more flaws. Each flawed good has

RUDIKE [14]

Answer:

1)

FLAW TYPE2 NO TYPE2 FLAW

TYPE1 0.015 0.025

NO TYPE1 FLAW 0.01 0.95

2) 0.04 and $0.04

3) 0.025 and $0.025

4) 0.015 and $0.015

5) 0.95 and $0.95

Step-by-step explanation:

Given that;

financial cost = $1

p(flaw) = 0.05

p(type 1 flaw / flaw) = 80% = 0.8

p(type 2 flaw / flaw) = 50% = 0.5

p( type 1 and 2 flaw/flaw) = 30% = 0.30

1) Bivariate Table

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw) = 0.05 × 0.5 = 0.025

p( type 1 and 2 flaw) = p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

p( only 1 flow) = 0.04 - 0.015 = 0.025

p( only 2 flow) = 0.025 - 0.015 = 0.01

THEREFORE the Bivariate Table;

FLAW TYPE2 NO TYPE2 FLAW

TYPE1 0.015 0.025

NO TYPE1 FLAW 0.01 0.95

2) probability and expectations of type 1 flaw?

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

Expected financial cost to the firm per good = $1 × 0.04 = $0.04

3) probability and expectation of Type 2 flaw

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw) = 0.05 × 0.5 = 0.025

Expected financial cost to the firm per good = $1 × 0.025 = $0.025

4) probability and expectations of Type 1 and 2 flaws

p( type 1 and 2 flaw) = p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

Expected financial cost to the firm per good = $1 * 0.015 = $0.015

5) probability and expectations of no flaws?

Probability of no flaw = P(No flaw) =95% = 0.95

Expected financial cost saved the firm per good due to no flaw

= $1 × 0.95 = $0.95

5 0

4 years ago

Data will be collected on the following variables. Which variable can be considered discrete? A. The height of a person B . The

kvv77 [185]

Answer: E: The number of books a person finished reading last month

Step-by-step explanation:

First, a discrete variable is a variable that only can take some given values in a set, the discrete variables are usually not dense, and a continuous variable is a variable that can take any value in a range (where the accepted values are dense).

So, for example, the set of the natural numbers is discrete, and the set of the real numbers can represent a continuous variable.

Here the only option that is really discrete will be the number of books that a person finished reading last month because here only positive whole numbers are accepted (you can not finish a 0.454 of a book)

The other options are continuous because all are classical measures.

For example, the weight of a person can jump between:

75.6kg and 75.7kg.

So you could think that this is discrete because the values between 75.6kg and 75.7g are not shown with our measuring device, but those will be added in the error of the measure because the weights between 75.6kg and 75.7kg are actually possible, so they must be accepted.

4 0

3 years ago

What number is in between 375 and 400?

Georgia [21]

376,377,378,379,380,381,382,383,384,385,386,387,388,389,390,391,392,393,394,395,396,397,398,399,400
just kidding its 396.5
hope this helped

7 0

3 years ago

Maylin goes to her local sporting goods store to buy socks and jogging shorts. Socks cost $10 per pair and jogging shorts cost

PolarNik [594]

Answer:

Maylin should purchase one unit of each socks & jogging shorts.

Step-by-step explanation:

In case of two goods, consumer is at equilibrium when marginal utility per dollar spent on last unit of the goods are equal, ie MU 1 / P1 = MU 2 / P2 (MU are the marginal utilities / marginal benefit of two goods, P are the price of two goods)

Given : MU1 (So) = 20, MU2 (JSh) = 30, P1 (So) = 10, P2 (JSh) = 15

So, equilibrium is at where MU1 (So) / P1 (So) = MU2 (JSh) / P2 (Jsh)

20/10 = 2, & 30/15 = 2. MU's per dollar are equal for both.

So Maylin is in equilibrium, she should purchase one unit of each socks & jogging shorts.

5 0

3 years ago