2√50 × 3√32 × 4√18
=2(5√2) × 3(4√2)× 4(3√2)
=2(5)(2)(3)(4)(4)(3√2)
=2880√2
10^6 = 10 *10*10*10*10*10 = 1,000,000
10^2 = 10*10 = 100
1000000/100 = 10,000 times larger
Answer:
Step-by-step explanation:
<u>Given system:</u>
The solution is the common area shaded by the inequalities.
The lines are parallel because of same slope.
Both lines are solid because of equal sign in both inequalities.
The first inequality has a y-intercept of 1 and shaded area is to the left of the line since the value of y is greater as x increases.
The second inequality has a y-intercept of -2 and shaded area is to the right of the line since the value of y is greater as x increases.
The matching graph is the second picture (or attached below) and there is no solution.
The new parking lot must hold twice as many cars as the previous parking lot. The previous parking lot could hold 56 cars. So this means the new parking lot must hold 2 x 56 = 112 cars
Let y represent the number of cars in each row, and x be the number of total rows in the parking lot. Since the number of cars in each row must be 6 less than the number of rows, we can write the equation as:
y = x - 6 (1)
The product of cars in each row and the number of rows will give the total number of cars. So we can write the equation as:
xy = 112 (2)
Using the above two equations, the civil engineer can find the number of rows he should include in the new parking lot.
Using the value of y from equation 1 to 2, we get:
x(x - 6) = 112 (3)
This equation is only in terms of x, i.e. the number of rows and can be directly solved to find the number of rows that must in new parking lot.
Answer:
3. 16
Explanation:
Factor the numerator and denominator and cancel the common factors.
