Answer:
Volume of the tank = 636 ft³
Step-by-step explanation:
Formula for the volume of a cylinder is,
V = πr²h
Where r = radius of the cylinder
h = height of the cylinder
By substituting the values of radius and height of the water tank given in the question,
V = 
= 202.5π
= 202.5 × (3.14)
= 635.85 ft³
≈ 636 ft³
Therefore, volume of the cylindrical water tank is 636 ft³.
Answer:
1.
Step-by-step explanation:
We can see that CD is angle bisector, So we will use angle bisector theorem which states that the angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle.
We can set up an equation as:

Upon substituting our given values we will get,
Cross multiplying our equation we will get,





Therefore, the length of AD is
units and 1st option is the correct choice.
When discriminant >0, then it contrains 2 distinct real zeros.
Discriminant=6 and 6>0 so, you have 2 solutions.
Answer:
x = 2.3
Measure of arc XY = 76° ⇒ answer (D)
Step-by-step explanation:
∵ arc XY congruent to arc YZ
∴ XY = YZ ⇒ chords subtended by equal arcs are equal
∴ 3x = 6.9 ⇒ x = 6.9/3
∴ x = 2.3
In ΔOXY
∵ OX = OY radii
∴ m∠OXY = m∠OYX
∵ m∠OXY = 52°
∴ m∠OYX = 52°
∵ The sum of angles of a Δ = 180°
∴ m∠XOY = 180 - 2 × 52 = 76°
∵ ∠XOY is central angle subtended by arc XY
∴ The measure of arc XY = m∠XOY = 76°
Answer: 37, 38, and 39
Step-by-step explanation: This problem states that the sum of 3 consecutive integers is 114 and it asks us to find the integers.
3 consecutive integers can be represented as followed.
X ⇒ <em>first integer</em>
X + 1 ⇒ <em>second integer</em>
X + 2 ⇒ <em>third integer</em>
<em />
Since the sum of our 3 consecutive integers is 114, we can set up an equation to represent this.
X + X + 1 + X + 2 = 114
We can simplify on the left side by combining the X's and the numbers.
3x + 3 = 114
-3 -3 ← <em>subtract 3 from both sides of the equation</em>
3x = 111
÷3 ÷3 ← <em>divide both sides of the equation by 3</em>
<em> </em>X = 37
X ⇒ <em>first integer = 37</em>
X + 1 ⇒ <em>second integer = 38</em>
X + 2 ⇒ <em>third integer = 39</em>
<em />
<em>Therefore, our 3 consecutive integers are 37, 38, and 39.</em>