All categories

3 years ago

Combine the like terms to create an equivalent expression: \large{3z+2+(-5z)+6}3z+2+(−5z)+6

Mathematics

1 answer:

rjkz [21]3 years ago

8 0

Answer:11z+20

Step-by-step explanation:3z+2-5z+18z+12-5z+6

Then u bring light terms together

16z+2+12-5z+6

11z+20

You might be interested in

A credit card company charges 18% simple interest for overdue accounts. How much interest will Kristen owe three months from now

Ber [7]

Answer: The amount that Kristen would owe three months from now is $67.5

Step-by-step explanation:

The formula for determining simple interest is expressed as

I = PRT/100

Where

I represents interest paid on the loan.

P represents the principal or the current balance.

R represents interest rate

T represents the duration for which the account is overdue in years.

From the information given,

P = 1500

R = 18%

T = 3 months = 3/12 = 0.25 year

I = (1500 × 18 × 0.25)/100 = $67.5

4 0

4 years ago

What is root -9 + root -12 written as a complex number in the form a + bi ?

patriot [66]

Answer:

Step-by-step explanation:

I assume you are talking about square roots when you say root...

Sqrt(-9) = 3i

Sqrt(-12) = 2Sqrt(3)i

Complex number is 3 + 2Sqrt(3) i

3 0

2 years ago

Prove algebraically that the straight line with equation x =2y+5 is a tangent to the circle with equation x ² +y ²

mrs_skeptik [129]

The intersection point is only one. Then the equation of the line is tangent to the circle at point (1, -2).

<h3>What is a circle?</h3>

It is a locus of a point drawn an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

Prove algebraically that the straight line with equation x = 2y + 5 is a tangent to the circle with equation x² + y² = 5.

x = 2y + 5 ...1

x² + y² = 5 ...2

If the intersection of the point of the circle and line is one. Then the line is tangent to the circle.

Then from equations 1 and 2, we have

(2y + 5)² + y² = 5

4y² + 25 + 20y + y² - 5 = 0

5y² + 20y + 20 = 0

5y² + 10y + 10y + 20 = 0

5y (y + 2) + 10(y + 2) = 0

(5y + 10)(y + 2) = 0

y = -2, -2

Then the value of y is unique then the value of x will be unique.

The value of x will be

x = 2(-2) + 5

x = -4 + 5

x = 1

The intersection point is only one. Then the equation of the line is tangent to the circle at point (1, -2).

More about the circle link is given below.

brainly.com/question/11833983

#SPJ1

4 0

2 years ago

Help with those three please!!

Scilla [17]

Answer:

Part 1) Option A. The axis of symmetry is x=4

Part 2) Option C. minimum

Part 3) Option A. (4,-4)

Part 4) Option B. (2,0) and (6,0)

Step-by-step explanation:

we have

$f(x)=x^{2}-8x+12$

Part 1) What is the axis of symmetry of the parabola described by the equation above?

we know that

The equation above is a vertical parabola open upward

The axis of symmetry is the x-coordinate of the vertex

Find the vertex of the parabola (convert the equation in vertex form)

$f(x)-12=x^{2}-8x$

$f(x)-12+16=x^{2}-8x+16$

$f(x)+4=x^{2}-8x+16$

$f(x)+4=(x-4)^{2}$

$f(x)=(x-4)^{2}-4$ ----> equation in vertex form

The vertex of the parabola is (4,-4)

The axis of symmetry is x=4

Part 2) The vertex of the equation above is also

we know that

The equation above is a vertical parabola open upward

therefore

The vertex is a minimum

Part 3) What is the vertex of the parabola described by the equation above

we know that

The equation of the parabola into vertex form is equal to

$f(x)=(x-4)^{2}-4$

therefore

The vertex of the parabola is (4,-4)

Part 4) What are the x-intercepts of the parabola described by the equation above

we know that

The x-intercepts are the values of x when the value of y is equal to zero

$f(x)+4=(x-4)^{2}$

f)x)=0

$4=(x-4)^{2}$

take square root both sides

$(x-4)=(+/-)2$

$x=4(+/-)2$

$x=4(+)2=6$

$x=4(-)2=2$

therefore

The x-intercepts are

(2,0) and (6,0)

7 0

3 years ago

Angle our ST is a right angle. Angle RSU has a measure of 25° what is the measure of angle TSU?

pochemuha

it is equal to a43q4fr4f434tc143 t43t

8 0

4 years ago