about what there is no question here....?
<span>the blank boxes are for you to plug in x=20 to prove its right.
so it would be
3(20)-4=2(20+8)
60-4=2(28)
56=56
so its true!</span>
Let x be the width so the length will be 2x-4 . The perimeter can be found by the equation x+x+(2x-4)+(2x-4)=58. Notice I repeated the length and the width twice because you know there are two lengths and two widths in a rectangle, so continue solving by combining like terms 6x-8=58 the add 8 to both sides 6x=66 then divide both sides by 6 to obtain x=11, that's the width but they are asking you for the length so we said the length could be found by the equation 2x-4, now plug in the 11, 2(11)-4 and solve 22-4 equals 18cm which is the length.
Answer:
40 and 28
Step-by-step explanation:
We have two unknown numbers, so let's call them x and y for now.
We know the sum of the two numbers is 68, and the difference is 12, so let's substitute those two numbers for x and y:
x+y=68
and
x-y=12
Because both of these systems are true, we can take both these equations and combine them, by adding each side of one equation with the corresponding side of the other.
So we have:
(x+y)+(x-y)=(68)+(12)
2x=80
x=40
Now we know one of the numbers, x, is equal to 40, so now we can plug that number back into one of the two original equations, x+y=68 or x-y=12. I'll choose x-y=12.
After plugging in x, we get:
40-y=12
-y=-28
y=28
So now we have figured out x and y, which are 40 and 28.
Answer:
The required equation is (1) and the number of boys is 211.
Step-by-step explanation:
Let the number of boys be x.
It is given that there are 100 more girls than boys. It means the number of girls is x+100.
The total number of students is 522.
Number of boys + Number of girls = 522
... (1)
Combine like terms.
Subtract 100 from both the sides.
Divide both sides by 2.
Therefore the required equation is (1) and the number of boys is 211.
