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3 years ago

Geometry

Mathematics

1 answer:

Snezhnost [94]3 years ago

5 0

Point B is the midpoint of line segment AC

so 2 * (AB) = AC

2(3x) = 5x + 21

6x = 5x + 21

x = 21

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Solve w + (-2) = -18 for w<br><br> (10 pts, Correct gets brainliest!)

loris [4]

Answer:

w = -16

Step-by-step explanation:

w + (-2) = -18

Add 2 to each side

w-2+2 = -18+2

w = -16

6 0

3 years ago

X^2-6x-4=0,

Rzqust [24]

Use quadratic formula since we can't factor

for 0=ax²+bx+c
$x= \frac{-b+/-\sqrt{b^2-4ac}}{2a}$

so, for
0=1x²-6x-4
a=1
b=-6
c=-4

$x= \frac{-(-6)+/-\sqrt{(-6)^2-4(1)(-4)}}{2(1)}$
$x= \frac{6+/-\sqrt{36+16}}{2}$
$x= \frac{6+/-\sqrt{52}}{2}$
$x= \frac{6+/-2\sqrt{13}}{2}$
$x= 3+/-\sqrt{13}$

the solutions are x=3+√13 and x=3-√13
or aprox
x≈6.61 and x≈-0.61

4 0

3 years ago

PLS GIVES <br><br> Moderate correlation definition and thank you :)

Len [333]

Answer:

Your welcomeeee :)

Step-by-step explanation:

When two variables correlate and when the value of one increases as the value of the other decreases we say the relationship between both variables shows a negative correlation

3 0

3 years ago

Help me on number 19 plz.

bulgar [2K]

Simply put 10 in all of the boxes. There are 5 boxes. And all those boxes equal 50, right? So for every box, there's 10 students. 10 multiplied by 5 is equal to 50.

8 0

4 years ago

Read 2 more answers

P=(\frac{\sqrt{x} +2}{x-1}+\frac{\sqrt{x}\\ -2}{x-2\sqrt{x} +1} ) : \frac{4x}{(x-1)^{2} }

balandron [24]

The solution to the division of the given surd is: $\mathbf{P =\dfrac{(6\sqrt{x}-x^2\sqrt{x}-3x\sqrt{x}+2x+2)(x-1) }{8x} }$

<h3>Division of Surds.</h3>

The division of surds follows a systemic approach whereby we divide the whole numbers separately and the root(s) are being divided by each other.

Given that:

$\mathbf{P=(\frac{\sqrt{x} +2}{x-1}+\frac{\sqrt{x}\\ -2}{x-2\sqrt{x} +1} ) : \frac{4x}{(x-1)^{2} }}$

i.e.

$\mathbf{=\dfrac{(\frac{\sqrt{x} +2}{x-1}+\frac{\sqrt{x}\\ -2}{x-2\sqrt{x} +1} )}{ \frac{4x}{(x-1)^{2} }} }$

Using the fraction rule:

$\mathbf{\dfrac{a}{\dfrac{b}{c}}= \dfrac{a\times c}{b}}$

$\mathbf{\implies \dfrac{(\frac{\sqrt{x} +2}{x-1}+\frac{\sqrt{x}\\ -2}{x-2\sqrt{x} +1} )(x-1)^{2}}{4x}} }$

By simplification, we have:

$\mathbf{ =\dfrac{\dfrac{(6\sqrt{x}-x^2\sqrt{x}-3x\sqrt{x}+2x+2)(x-1) }{2} }{4x} }$

$\mathbf{P =\dfrac{(6\sqrt{x}-x^2\sqrt{x}-3x\sqrt{x}+2x+2)(x-1) }{8x} }$

Learn more about evaluating the division of surds here:

https://brainly.in/question/27942899

#SPJ1

6 0

2 years ago