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3 years ago

A cylinder and its dimensions are shown below.

Mathematics

1 answer:

Bumek [7]3 years ago

4 0

Answer:

$(A) B=\pi (12.1)^2$

Step-by-step explanation:

Given a cylinder with the following dimensions

Radius of the Cylinder =12.1 cm

Height of the Cylinder =3.8cm

Volume of a cylinder = Base Area X Height

The base area is a circle, therefore the expression that can be used to find the value of B, (in square centimeters), for this cylinder is given as:

$Base Area =\pi r^2\\B=\pi (12.1)^2$

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I need help please with theirs question

crimeas [40]

Answer:

Step-by-step explanation:

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3 years ago

I need help? With proof for this one.

Schach [20]

Answer:

See below.

Step-by-step explanation:

ABC is an isosceles triangle with BA = BC.

That makes angles A and C congruent.

ABD is an isosceles triangle with AB = AD.

That makes angles ABD and ADB congruent.

Since m<ABD = 72 deg, then m<ADB = 72 deg.

Angles ADB and CDB are a linear pair which makes them supplementary.

m<ADB + m<BDC = 180 deg

72 deg + m<BDC = 180 deg

m<CDB = 108 deg

In triangle ABD, the sum of the measures of the angles is 180 deg.

m<A + m<ADB + m<ABD = 180 deg

m<A + 72 deg + 72 deg = 180 deg

m<A = 36 deg

m<C = 36 deg

In triangle BCD, the sum of the measures of the angles is 180 deg.

m<CBD + m<C + m<BDC = 180 deg

m<CBD + 36 deg + 108 deg = 180 deg

m<CBD = 36 deg

In triangle CBD, angles C and CBD measure 36 deg making them congruent.

Opposite sides DB and DC are congruent making triangle BCD isosceles.

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2 years ago

Find the nth term for the sequence 30 27 24 21

patriot [66]

Assuming that the 30 is term #1 ..... The 'n'th term of the series is. T(n) = 33 - 3n or 3 (11 - n).

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3 years ago

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How do you write 0.166666... as a fraction?

nadya68 [22]

Answer:

0.166666 in fraction form is 83333/500000.

Step-by-step explanation:

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3 years ago

Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca

KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean breaking weight = 768.2 lb

s = sample standard deviation = 15.1 lb

n = sample of cables = 45

$\mu$ = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.02 < $t_4_4$ < 2.02) = 0.95 {As the critical value of t at 44 degree

of freedom are -2.02 & 2.02 with P = 2.5%}

P(-2.02 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.02) = 0.95

P( $-2.02 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $768.2-2.02 \times {\frac{15.1}{\sqrt{45} } }$ , $768.2+2.02 \times {\frac{15.1}{\sqrt{45} } }$ ]

= [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0

3 years ago