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3 years ago

1) Is this graph a linear function? Explain.....2) Is this graph a linear function? Explain....

Mathematics

1 answer:

Sav [38]3 years ago

6 0

9514 1404 393

Answer:

Step-by-step explanation:

If the graph is not a straight line, it is not a linear function. Neither graph 1 nor graph 2 is a straight line, so neither is a linear function.

Graph 2 is made of parts of two straight lines. It is not one straight line, so not a linear function. It is called "piecewise linear," which is different.

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3(x-5)=2(x-10)<br> Solce for X

stira [4]

Answer: X = -5

Step-by-step explanation:

3(x-5)=2(x-10)

3x - 15 = 2x -20

3x = 2x -5

x = -5

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3 years ago

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viva [34]

109 with a remainder of 6
Please give brainliest

7 0

3 years ago

Please help

user100 [1]

Answer:

Length of garden will be 30 metres.

Step-by-step explanation:

Let the Width of garden be x metres.

then,

Length of garden will be (x+6) metres.

Area = Length × Breadth

720 = x X (c+6)

720 = x²+6x

0 = x²+6x-720

As we can see above equation is a quadratic equation in the form of ax²+bx+C.

so,

$= \frac{ - b ± \sqrt{{b}^{2} - 4ac} }{2a} \\ = \frac{ - 6 ± \sqrt{{6}^{2} - 4 \times 1 \times - 720} }{2} \\ = \frac{ - 6 ± \sqrt{36 + 2880} }{2} \\ = \frac{ - 6 ± \sqrt{2916} }{2} \\ = \frac{ - 6 ± 54}{2}\\= \frac{-6+54}{2} ... \frac{ - 6 - 54}{2} \\ = \frac{48}{2} ... \frac{ - 60}{2} \\ = 24... - 30$

One of the Roots of the Quadratic equation is 24 and other is -30.

And as we know width of any garden cannot be negative so the width of garden will be 24 metres.

As we got the width,

adding 6 to it will give us the Length,

So,

24 metres + 6 = 30 metres.

Length of the garden is 30 metres.

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4 years ago

Complete the square and wright in standard form x^2+y^2-8x-12+52=36

Sphinxa [80]

X² + y² - 8x - 12y + 52 = 36
x² - 8x + y² - 12y + 52 = 36
x² - 8x + y² - 12y = 88
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(x - 4)² + (y - 6)² = 138
(h, k) = (x, y) = (4, 6)

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3 years ago

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What is the best result for h?

Kryger [21]

Answer: First option.

Step-by-step explanation:

To solve for "h" from the given the equation $S=2\pi rh+2\pi r^2$ , you need to:

Apply the Subtraction property of equality and subtract $2\pi r^2$ to both sides of the equation.

Then you need to apply the Division property of equality and divide both sides of the equation by $2\pi r$ .

Then:

$S-2\pi r^2=2\pi rh+2\pi r^2-2\pi r^2\\\\S-2\pi r^2=2\pi rh\\\\\frac{S}{2\pi r}-\frac{2\pi r^2}{2\pi r}=\frac{2\pi rh}{2\pi r}\\\\\frac{S}{2\pi r}-r=h$

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3 years ago

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