Question

What is the slope of the line whose equation is 2x-3y=5

Answer 1

Answer:

$\large\boxed{\text{The slope}\ m=\dfrac{2}{3}}$

Step-by-step explanation:

The slope-intercept form of a line:

$y=mx+b$

m - slope

b - y-intercept

We have the standard form of a line:

$2x-3y=5$

Convert to the slope-intercept form:

$2x-3y=5$          subtract 2x from both sides

$-3y=-2x+5$        divide both sides by (-3)

$y=\dfrac{-2}{-3}x+\dfrac{5}{-3}\\\\y=\dfrac{2}{3}x=-\dfrac{5}{3}\to m=\dfrac{2}{3}$

Answer 2

Answer:

Step-by-step explanation:

subtract 2x from both sides of the equation

-3y=-2x+5

Divide each by -3 and simplify

- 3y/-3=-2x/-3+5/-3

reduce and cancel the common numbers

move the negative over from the denominator

-(-1*y)= - 2x/-3 +5/-3

simplify

- -2x/3

multiply  2x/3 by 1

y=2x/3+5/-3

move the negative in front of fraction

y=2x/3 -5/3

slope intercept form

y=2/3 x -5/3

the slope is 2/3