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navik [9.2K]
2 years ago
11

Pls hurry by Friday! Whoever answers first will get points

Mathematics
1 answer:
leonid [27]2 years ago
3 0

Answer:

14 inches for every side

Step-by-step explanation:

44/4 = 22

circumfrence of half circle is 3.14r = 22

22/3.14 is about 7

the radius is half the side length so multiply 7 by 2 to get 14

mark brainliest please

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Solve using substitution.<br> y = -2<br> -7x - y = -5
Natasha_Volkova [10]

Step-by-step explanation:

- 7x - ( - 2) =  - 5 \\  - 7x + 2 =  - 5 \\  - 7x =  - 7 \\ x = 1 \\

5 0
2 years ago
Anyone help me with this?
den301095 [7]

h = 4(x+3y) + 2

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4×3y= 12y

4x+12y+2

x= \frac{12y+2}{4} \\\

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2 years ago
Find the correct answer to this
Zigmanuir [339]

Answer:

the rise/ run would be 3/3

Step-by-step explanation:

3 0
2 years ago
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Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the
motikmotik

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

<u>Coordinates of the point A':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point A(-2,3), we get;

(-2,3)\rightarrow (-2,-3)

Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point B(0,3), we get;

(0,3)\rightarrow (0,-3)

Thus, the coordinates of the point B' is (0,-3)

<u>Coordinates of the point C':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point C(-1,-1), we get;

(-1,-1)\rightarrow (-1,1)

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

8 0
3 years ago
#18 how would u not multiplying to find which is grater
Snowcat [4.5K]
In the first product the numerator of the fraction is greater than the denominator, therefore the fraction is greater than 1. On the other hand in the second product the numerator of the fraction is smaller than the denominator, therefore the fraction is smaller than one. That means the first product is greater than the second one.
3 0
3 years ago
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