Answer:
Left side of graph of function would be up .
Step-by-step explanation:
Given : .
To find : In which direction does the left side of the graph of this function point.
Solution : We have given that .
We can see from the given function Degree is even and leading coefficient is positive .
By the behavior of end points : left side of graph would be up .
Therefore, left side of graph of function would be up .
Answer:
A. (-1, -4)
Step-by-step explanation:
The vertex can be found by converting the equation from standard form to vertex form.
<h3>Vertex</h3>Considering the x-terms, we have ...
y = (x^2 +2x) -3
where the coefficient of x is 2. Adding (and subtracting) the square of half that, we get ...
y = (x^2 +2x +(2/2)^2) -3 -(2/2)^2
y = (x +1)^2 -4
Compare this to the vertex form equation ...
y = a(x -h)^2 +k
which has vertex (h, k).
We see that h=-1 and k=-4. The vertex is (h, k) = (-1, -4).
On the attached graph, the vertex is the turning point, the minimum.
