You can use Heron Formula in the calculator to output the result, but i still show you the steps on paper thro
lengths of the 3 lines: \sqrt{392} , \sqrt{676} , \sqrt{676}
s= (\sqrt{392} + \sqrt{676} + \sqrt{676})/2=35.89949494
area= \sqrt{s(s- \sqrt{392} )(s- \sqrt{676})^2 } =238
This needs to be 20 characters long but it’s 4/3
Once she completes a wall, Sabrina notices that the number of squares along each side of the wall is equal to the number of square centimeters in each tile’s area. Write an equation for the number of squares on the wall, SW, in terms of c. Then, solve for the number of squares on the wall
g. Write an equation for the area of the wall, Aw. Then solve for the area of the wall.
E=mc2 is one of the most recognizable equations in the world. In this task, you’ll attempt to understand it better. Let’s start with what the letters mean. The letter E stands for energy, the letter m stands for mass, and the letter c stands for the speed of light. The meaning of this equation is that you can completely convert mass into energy.
a. Rewrite the equation to solve for the speed of light, c. Use rational exponents instead of roots.
b. Using the properties of exponents, apply the rational exponent to the numerator and the denominator, and then rationalize the denominator.
c. Rewrite this equation without writing it as a fraction. (Fractional exponents are OK, though.)
d. Using whichever equation you prefer (part a, b, or c), find the speed of light in meters per second if a mass of 3 kilograms converts to 2.7 × 10^17 joules (J = kg·m^2/s^2
Answer
Midpoint = (3, 5.5)
Step by step explanation
Here we have to use the midpoint formula.
Midpoint = (
)
Here the point A = (-1, 8) and B = (7, 3)
x1 = -1, y1 = 8, x2 = 7 and y2 = 3
Now plug in these values into the formula.
Midpoint = (![\frac{-1 + 7}{2} , \frac{8 + 3}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%20%2B%207%7D%7B2%7D%20%2C%20%5Cfrac%7B8%20%2B%203%7D%7B2%7D)
= (6/2, 11/2)
= (3, 5.5)
Therefore, the midpoint the line segment AB is (3, 5.5)
Thank you.
The lateral area is 1560 cm².
The lateral area is the area of the lateral faces (the faces that are not bases). The dimensions of these are:
24 by 26
10 by 26
26 by 26
These are all rectangles. The area of each rectangle is given by length * width:
24*26 = 624
10*26 = 260
26*26 =676
624+260+676=1560