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Angelina_Jolie [31]
4 years ago
5

Graph the circle x2 + y2 – 14x – 12y + 76 = 0.

Mathematics
1 answer:
nikklg [1K]4 years ago
7 0

Answer:

The answer is, the center is (7,6) and the radius 3 soo, you would count three from the center to the arc( outer line and then if its three than ur good. proven in khan academy don't worry

Step-by-step explanation:

XD finally no more schoooooolllllllll baaaabbyyyyyy

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Round 55,553.65478 to:<br> a. hundreds<br> and<br> b. thousandths
zhenek [66]

Answer:

a. hundreds

55,600

b. thousandths

55,553.65500

5 0
3 years ago
Answer please someone
pantera1 [17]
∛11 ≈ 2.22398

Easily found using any scientific calculator or by typing "cube root of 11" into a Google search box.

As a number with an exponent, it would be
  11^{\frac{1}{3}}

5 0
3 years ago
Angle T had a measure between 0 and 360 and is coterminal with -170 angle. What is the measure of angle T?
Alika [10]

Answer: The answer is 190°.


Step-by-step explanation: We are to find the measure of ∠T which lies between 0° and 360° and is co-terminal with an angle of measure -170°.

We know that two angles are said to be co-terminal if one is obtained from the other by either adding or subtracting 360°.

So, angles which are co-terminal with -170° are

-170° + 360° = 190°,  -170° - 360° = 530°, etc.

Since 190° lies between 0° and 360°, so measure of ∠T is 190°.

Thus, the answer is 190°.


5 0
3 years ago
Consider the following argument: If pigs have wings, then pigs can fly. If pigs are lighter than air, then pigs can fly. Pigs ha
Darina [25.2K]

Answer:

a ) If r ⇒ p

    If q ⇒ p

    r ∪ q

    If r∪p ⇒ ¬ r

   ∴ s

b) The argument is invalid

Step-by-step explanation:

The argument is invalid because we do not with precision if b), because we do not have enough information about it, and this is because the previous sentences does not mention information about the donkey. We cannot infer something when we do not have enough information.

3 0
3 years ago
Match the polynomial expression on the left with the simplified version on the right.
Vitek1552 [10]

Given the following question:

First expression:

\begin{gathered} \frac{12x^3-14x^2+16x-8}{3x-2} \\ \text{ Factor the expression:} \\ 12x^3-14x^2+16x-8=2(6x^3-7x^2+8x-4) \\ \frac{2\left(6x^3-7x^2+8x-4\right)}{3x-2} \\ \text{ Factor:} \\ 2\left(6x^3-7x^2+8x-4\right)=(3x-2)(2x^2-x+2) \\ =(3x-2)(2x^2-x+2)=2\left(3x-2\right)\left(2x^2-x+2\right) \\ \frac{2\left(3x-2\right)\left(2x^2-x+2\right)}{3x-2} \\ \text{ Cancel the common factor:} \\ -(3x-2) \\ 4x^2-2x+4 \end{gathered}

Second expression:

3 0
1 year ago
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