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3 years ago

What situation can be represented by the expression-3 + 3?

Mathematics

2 answers:

ivanzaharov [21]3 years ago

7 0

Correct, c and e. they are the only ones that make sense

SashulF [63]3 years ago

4 0

Answer:

Step-by-step explanation: It B

-3 + 3 = 0

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Jack says 0.90 is between 0.9 and 0.91. Is he correct? Explain.

OleMash [197]

Well, 0.90 is actually equal to 0.9. It is less than 0.91 and equal to 0.9 so that means it is not correct.

I hope this helps:)

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3 years ago

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otez555 [7]

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3 years ago

Read 2 more answers

A group of 59 randomly selected students have a mean score of 29.5 with a standard

algol [13]

Answer:

$29.5-1.671\frac{5.2}{\sqrt{59}}=28.37$

$29.5+1.671\frac{5.2}{\sqrt{59}}=30.63$

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

Step-by-step explanation:

Information given

$\bar X = 29.5$ represent the sample mean

$\mu$ population mean

s= 5.2 represent the sample standard deviation

n=59 represent the sample size

Confidence interval

The confidence interval for the true mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=59-1=58$

The Confidence interval is 0.90 or 90%, the significance is $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value is $t_{\alpha/2}=1.671$

Now we have everything in order to replace into formula (1):

$29.5-1.671\frac{5.2}{\sqrt{59}}=28.37$

$29.5+1.671\frac{5.2}{\sqrt{59}}=30.63$

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

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2 years ago

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marysya [2.9K]

The answer is c hope this helps

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