-15x - 3y = 3
-15x - 3(5x-1) = 3 [input y]
-15x - 15x - 3 = 3 [distribute 3 over 5x and -1]
-30x - 3 = 3 [combine like terms]
-30x = 6 [add 3 to eliminate the negative]
x =
[divide by -30 to get x alone]
x =
[reduce the fraction]
Hopefully this is helpful enough to get you to your answer
Answer:
hi :):):):):):):):) don't ignore me T_T
Step-by-step explanation:
Answer:
sorry j don't have my calculator but
sine of angle x°=opposite 6cm/9cm
byee
Answer:
No, to be a function a relation must fulfill two requirements: existence and unicity.
Step-by-step explanation:
- Existence is a condition that establish that every element of te domain set must be related with some element in the range. Example: if the domain of the function is formed by the elements (1,2,3), and the range is formed by the elements (10,11), the condition is not respected if the element "3" for example, is not linked with 10 or 11 (the two elements of the range set).
- Unicity is a condition that establish that each element of the domain of a relation must be related with <u>only one</u> element of the range. Following the previous example, if the element "1" of the domain can be linked to both the elements of the range (10,11), the relation is not a function.
Answer:
thats a long question
Step-by-step explanation:
sorry I'm doing a competition for who ever reaches 1k points
