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lesya [120]
3 years ago
6

(07.01 MC)

Mathematics
2 answers:
OverLord2011 [107]3 years ago
4 0

Answer: 12/5

Step-by-step explanation:

jekas [21]3 years ago
3 0

Tangent = Opposite over adjacent.

The opposite side of ∅ is 12 and the adjacent side is 5

The tangent becomes:

Tan(∅) = 12/5

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What is the range of this graph
Arlecino [84]

Answer:

[0,12]

Step-by-step explanation:

7 0
3 years ago
5. Kalen is trying to find the average of three measurements. The measurements are 13.8, 15.64, and 22.51. He adds the
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Answer:

if rounding by tenths 17.3 i’d rounding by hundredths 17.31 and thousandths 17.316

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7 0
4 years ago
Use the identity below to complete the tasks:
quester [9]

Answer:

a=[2q^{2}r]

b=[3s^{2}t]

Step-by-step explanation:

we have

8q^{6}r^{3}+27s^{6}t^{3}

we know that

8q^{6}r^{3}=(2^{3})(q^{2})^{3}r^{3}=[2q^{2}r]^{3}

27s^{6}t^{3}=(3^{3})(s^{2})^{3}t^{3}=[3s^{2}t]^{3}

therefore

a=[2q^{2}r]

b=[3s^{2}t]

substitute

a^{3} +b^{3}=(a+b)(a^{2} -ab+b^{2})

[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([2q^{2}r]^{2} -[2q^{2}r][3s^{2}t]+[3s^{2}t]^{2})

[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([4q^{4}r^{2}] -6[q^{2}r][s^{2}t]+[9s^{4}t^{2}])

7 0
3 years ago
Read 2 more answers
If the product of two positive numbers is forty eight, and one number is two greater than the other, what are the two numbers?
zaharov [31]
The two numbers are eight and six
3 0
3 years ago
Solve the equation 3 x+5 y=16 for y
Liono4ka [1.6K]

Answer:

Y = (16 - 3x)/5

Step-by-step explanation:

3x + 5y = 16

subtract 3x from both sides:

16-3x = 5y

divide both sides by 5:

(16 - 3x) / 5 = y

hope this helps

8 0
3 years ago
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