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AleksAgata [21]
2 years ago
14

What is the value of X?R=120 degreesT=130 degreesX=blank degrees

Mathematics
1 answer:
Ainat [17]2 years ago
4 0
X =blank degrees is the answer
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More comparing decimals
Lisa [10]

When comparing, think of the signs as a crocodile. A crocodile will want to eat greater (bigger) numbers than smaller numbers. So, you can think of it as that way.

2. 0.5 < 0.8 ... 0.8 is greater than 0.5

5. 0.7 = 0.70 ... This is same. 0.70 just has an extra 0 which you don't need.

8. 2.9 > 2.8 ... 2.9 is greater since 9 is bigger than 8.

11. 0.65 > 0.36 ... 65 is greater than 36. Therefore, 0.65 is greater.

14. 4.50 > 4.05 ... 4.50 has a five in the tenth place. 4.05 has five in the hundredth place.

17. 6.01 < 6.1 ... 6.1 has a one in the tenth place. 6.01 has a one in the hundredth place.

5 0
3 years ago
Find an equation for the line tangent to the curve at the point defined by the given value of d²y/dx².​
mars1129 [50]

Answer:

Step-by-step explanation:

Given:

x = 2cost,

t = (1/2)arccosx

y = 2sint

dy/dx = dy/dt . dt/dx

dy/dt = 2cost

dt/dx = -1/√(1 - x²)

dy/dx = -2cost/√(1 - x²)

Differentiate again to obtain d²y/dx²

d²y/dx² = 2sint/√(1 - x²) - 2xcost/(1 - x²)^(-3/2)

At t = π/4, we have

(√2)/√(1 - x²) - (√2)x(1 - x²)^(3/2)

4 0
3 years ago
If DE≅EF, CD = v + 45, and CF = 4v, what is the value of v?
irinina [24]

Answer:

<h2><u>since </u><u>DE≅EF</u></h2>

<u>CD=</u><u>CF </u><u>(</u><u>cpct)</u>

<u>v + 45 = 4v \\ 4v - v = 45 \\ 3v = 45 \\ v =  \frac{45}{3}  \\  v = 15</u>

<h2><u>hope</u><u> it</u><u> helps</u><u> you</u><u><</u><u>3</u></h2>
3 0
3 years ago
Tonya said that the fraction 10/12 was in simplest form. Do you agree? Why or why not?
Zarrin [17]

Answer:

NO

Step-by-step explanation:

You can reduce the fraction by dividing by 2. If you divide by 2, then you will get 5/6 which is more reduced than 10/12.

Hope  this helps plz mark brainliest if correct :D

7 0
3 years ago
Read 2 more answers
I need help plz do each problem
Aleks [24]
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2. 30-10x
3. 3m+3n
4. 8+2j
3 0
2 years ago
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