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brilliants [131]
4 years ago
12

Charlie speed of 3 yd/s about how manymiles per hour does charlie run all

Mathematics
1 answer:
Vinvika [58]4 years ago
3 0

(3 yd/sec) x (1 mile / 1,760 yd) x (3,600 sec/hour) =  6.136 mph (rounded)
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What is 2 and 5/14 divided by (2 and 5/8 times 1 and 3/7)?
Lina20 [59]
(2 5/14) / (2 5/8 * 1 3/7)....turn them all into improper fractions
(33/14) / (21/8 * 10/7)
(33/14) / (105/28)...when dividing fractions, flip what u r dividing by, then multiply
33/14 * 28/105 = 132/210 reduces to 22/35 <==
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One-third of a number is 7. Find the number.
Paraphin [41]

Answer:

21

Step-by-step explanation:

21/3 = 7

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Two classrooms are sharing seven packages of unit cubes if the packages are split evenly how many packages with each classroom r
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We have two classrooms and seven packages.

This means we need to divide the seven packages in half (two pieces).

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In the right triangle PQR, sin P = 0.8. what is the length of RP?
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4 years ago
Pluto's distance P(t)P(t)P, left parenthesis, t, right parenthesis (in billions of kilometers) from the sun as a function of tim
Xelga [282]

Answer: P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:

y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D

where:

A is amplitude A=|A|

B is related to the period by: T = \frac{2.\pi}{B}

C is the phase shift or horizontal shift: \frac{C}{B}

D is the vertical shift

In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.

<u>Amplitude</u>:

a = \frac{largest - smallest}{2}

At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:

a = \frac{6.9-4.4}{2}

a = 1.25

<u>b</u>

A time period for Pluto is T=66 years:

66 = \frac{2.\pi}{b}

b = \frac{\pi}{33}

<u>Vertical</u> <u>Shift</u>

It can be calculated as:

d = \frac{largest+smallest}{2}

d = \frac{6.9+4.4}{2}

d = 5.65

Knowing a, b and d, substitute in the equivalent positions and find P(t).

P(t) = a.sin(b.t) + d

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

8 0
3 years ago
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