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san4es73 [151]
3 years ago
8

NEED HELP ASAP!!! Solve 0 = (3x - 4) / 5

Mathematics
1 answer:
DENIUS [597]3 years ago
5 0

answer: 1.13622

Step by step explanation:

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Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.
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Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let \mu = <u><em>mean commute time in the U.S..</em></u>

So, Null Hypothesis, H_0 : \mu \geq 30 minutes      {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, H_A : \mu < 30 minutes     {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean commute time = 27.6 minutes

            s = sample standard deviation = 19.6 minutes

            n = sample of people from the 2000 U.S. Census = 500

So, <u><em>the test statistics</em></u>  =  \frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }  ~ t_4_9_9

                                       =  -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis.</u>

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

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If u just give me my fricking points its 91
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A veterinarian wishes to compare the number of times race horses are reported to be lame during a 12‑month period, as compared w
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Answer:

Step-by-step explanation:

Hello!

The objective of the veterinarian is to check if racing contributes to lameness in racing horses. To conduct a test the veterinarian should select at random two groups of horses, group one will be of racing horses and group two should be of not racing horses. Other than racing, all the other differences between the horses that may cause lame or resistance to lame should be controlled( confounding variables) such as age, breed, the number of weakly hours spent exercising, diet, obstacle-free environment, etc...

This type of study is an experimental design.

The experimental design is an analytic essay characterized by the fact that the investigator controls the study variable and the randomization of the samples. In which all the variables are controlled except the ones that you wish to study.

I hope it helps!

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