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Thepotemich [5.8K]

2 years ago

13

Mr. Hebert's class has 36 students and Ms. Green's class has 30 students. For a class competition, each class must be divided in

to teams with the same number of students on every team. What is the largest team size possible for both classes?
Question 4 options:

33

5

6

12

1 answer:

Dominik [7]2 years ago

8 0

Answer: try question cove just saying

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Ms. Tyson has a part time job selling cars. She earns a commission of 0.6% on all her sales. If her sales for last week was $281

In-s [12.5K]

Based on the information given her commission check is $1,689.8.

Using this formula

Commission check=Commission earned× Sales

Where:

Commission earned=0.6% or 0.006

Sales=$281,634

Let plug in the formula

Commission check= 0.006×$281,634

Commission check=$1,689.8

Inconclusion her commission check is $1,689.8.

Learn more here:brainly.com/question/24030244

8 0

2 years ago

Please help me I’m stuck

FrozenT [24]

Answer:

10.77 units

Step-by-step explanation:

By imaging an imaginery line at point before 1 units to be 4 units: b = 4 units

Therefore h = 11 - 1 = 10 units

Using Pythagoras theorem:

x² = h² + b² = 10² + 4² = 100 + 16 = 116

x = √116 = 10.77 units

8 0

2 years ago

What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?

Trava [24]

Answer:

$\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}$

Step-by-step explanation:

The explicit formula for a geometric sequence:

$a_n=a_1r^{n-1}$

$a_n$ - n-th term

$a_1$ - first term

$r$ - common ratio

$r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}$

We have

$a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...$

The common ratio:

$r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}$

<h2>It's not a geometric sequence.</h2>

If $a_3=-\dfrac{1}{16}$ then the common ratio is $r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}$

Put to the explicit formula:

$a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}$

Put $a_n=\dfrac{1}{1024}$ and solve for <em>n </em>:

$-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1$

$\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6$

5 0

3 years ago

What type(s) of symmetry is/are shown in the figure below

Anestetic [448]

Answer:

horizontal

Step-by-step explanation:

as it's horizontal

8 0

1 year ago

Write an algebraic expression of the verbal expression the quotien of five times x and fifteen

faust18 [17]

5x+ (5)15

or

5(x+15)

I hope this helps

4 0

2 years ago