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ololo11 [35]
3 years ago
10

The beginning checkbook balance of Gregory Co. was $3,045.58. Their bank statement indicated a balance of $4,262.92. The bookkee

per of Gregory Co. discovered a $220.05 deposit not reflected on the statement and checks numbered 478 and 492 in the amounts of $325.50 and $497.65 still outstanding. The bank credited Gregory’s account for $651.84 for a note that they had collected. The bank charged their account $37.60 for printed checks. Their reconciled balance was (Remember: To reconcile the bank balance with the checkbook balance means to compare the two, make the necessary adjustments (debits and credits) and ensure that the two amounts are equal.)
$3,569.82. $3,659.28. $3,659.82. $6,359.82.
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:

$3,659.82

Step-by-step explanation:

Adding to the checkbook those debits and credits not already there brings its balance to ...

... $3045.58 +651.84 -37.60 = $3659.82

Adjusting the bank's balance by the deposits and checks not already there brings its balance to ...

... $4262.92 +220.05 -325.50 -497.65 = $3659.82

Thus, the reconciled accounts will agree on the balance $3659.82.

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Stuart has some 2- ounce, 3- ounce, and 4- ounce weights. How many different ways can Stuart combine the weights to make a total
podryga [215]
2,3,4
1st way: 6*2oz=12oz
2nd way: 3*2oz+2*3oz=12oz
3rd way: 4*2oz+4oz=12oz
4th way: 2*2oz+2*4oz=12oz
5th way: 4*3oz=12oz
6th way: 2*3oz+2oz+4oz=12oz
7th way: 3*4oz=12oz
Stuart can combine 2oz, 3oz and 4oz weigths 7 different ways to get 12oz.

8 0
3 years ago
Lamaj is rides his bike over a piece of gum and continues riding his bike at a constant rate time = 1.25 seconds the game is at
Hitman42 [59]

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. At time = 1.25 seconds, the gum is at a maximum height above the ground and 1 second later the gum is on the ground again.

a. If the diameter of the wheel is 68 cm, write an equation that models the height of the gum in centimeters above the ground at any time, t, in seconds.

b. What is the height of the gum when Lamaj gets to the end of the block at t = 15.6 seconds?

c. When are the first and second times the gum reaches a height of 12 cm?

Answer:

Step-by-step explanation:

a)

We are being told that:

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. This keeps the wheel of his bike in Simple Harmonic Motion and the Trigonometric equation  that models the height of the gum in centimeters above the ground at any time, t, in seconds.  can be written as:

\mathbf {y = 34cos (\pi (t-1.25))+34}

where;

y =  is the height of the gum at a given time (t) seconds

34 = amplitude of the motion

the amplitude of the motion was obtained by finding the middle between the highest and lowest point on the cosine graph.

\mathbf{ \pi} = the period of the graph

1.25 = maximum vertical height stretched by 1.25 m  to the horizontal

b) From the equation derived above;

if we replace t with 1.56 seconds ; we can determine the height of the gum when Lamaj gets to the end of the block .

So;

\mathbf {y = 34cos (\pi (15.6-1.25))+34}

\mathbf {y = 34cos (\pi (14.35))+34}

\mathbf {y = 34cos (45.08)+34}

\mathbf{y = 58.01}

Thus, the  gum is at 58.01 cm from the ground at  t = 15.6 seconds.

c)

When are the first and second times the gum reaches a height of 12 cm

This indicates the position of y; so y = 12 cm

From the same equation from (a); we have :

\mathbf {y = 34 cos(\pi (t-1.25))+34}

\mathbf{12 = 34 cos ( \pi(t-1.25))+34}

\dfrac {12-34}{34} = cos (\pi(t-1.25))

\dfrac {-22}{34} = cos(\pi(t-1.25))

2.27 = (\pi (t-1.25)

t = 2.72 seconds

Similarly, replacing cosine in the above equation with sine; we have:

\mathbf {y = 34 sin (\pi (t-1.25))+34}

\mathbf{12 = 34 sin ( \pi(t-1.25))+34}

\dfrac {12-34}{34} = sin (\pi(t-1.25))

\dfrac {-22}{34} = sin (\pi(t-1.25))

-0.703 = (\pi(t-1.25))

t = 2.527 seconds

Hence, the gum will reach 12 cm first at 2.527 sec and second time at 2.72 sec.

7 0
3 years ago
Please answer this i really understand this at all its so hard:((
vlabodo [156]

Step-by-step explanation:

25x ratio

stay safe and wear mask

5 0
2 years ago
Mr.sanchez drives 120 miles in 3 hours. At the same rate, how far will he drive in 5 hours
Rina8888 [55]
To elaborate:

To do this problem, we assume that Mr. Sanchez is driving at a constant rate.

According to this information, he has driven 120 mi in 3 hr. To find how much he drives in 5 hr, we first have to find how many mi he drives in 1 hour. To do this, we divide 120 miles by 3 hours, since we assume that he managed to drive an equal amount in each hour.

120/3=40

Therefore Mr. Sanchez drove at a rate of 40 mph.

However, this isn't the final answer. 40 miles is the distance for one hour of driving. To find the distance for 5 hours, we have to multiply the distance by 5 as well.

40 times 5=200

In conclusion, Mr. Sanchez will drive 200 miles in 5 hours.
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3 years ago
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Each statement describes a transformation of the graph of y = x. Which statement correctly describes the graph of y = x + 10?
scoray [572]

Answer:

C

Step-by-step explanation:

since it is the slope form y = mx+b

b = y axis

so in order to go up you have to translate upwards

hope this helped ;)

8 0
2 years ago
Read 2 more answers
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