Answer:
Rectangular area as a function of x : A(x) = 200*x + 2*x²
A(max) = 5000 m²
Dimensions:
x = 50 m
l = 100 m
Step-by-step explanation:
"x" is the length of the perpendicular side to the wall of the rectangular area to be fenced, and we call "l" the other side (parallel to the wall of the barn) then:
A(r) = x* l and the perimeter of the rectangular shape is
P = 2*x + 2*l but we won´t use any fencing material along the wll of the barn therefore
P = 2*x + l ⇒ 200 = 2*x + l ⇒ l = 200 - 2*x (1)
And the rectangular area as a function of x is:
A(x) = x * ( 200 - 2*x) ⇒ A(x) = 200*x + 2*x²
Taking derivatives on both sides of the equation we get:
A´(x) = 200 - 4*x ⇒ A´= 0
Then 200 - 4*x = 0 ⇒ 4*x = 200 ⇒ x = 50 m
We find the l value, plugging the value of x in equation (1)
l = 200 - 2*x ⇒ l = 200 - 2*50 ⇒ l = 100 m
A(max) = 100*50
A(max) = 5000 m²
A=(a+b)*h*1/2=(20+8)*7*1/2=49 m2
V=A*H=49*2=98 m3
Answer:
19,27 cm^2
Step-by-step explanation:
area of triangle = (6 x 3)/ 2 = 9 cm^2
circle area : 3^2 x 3,14 = 28,27 cm^2
area of shaped region = 28,27 - 9 = 19,27 cm^2
ΔHGE and ΔFGE are congruent by the Angle-Side-Angle Congruence Theorem (ASA).
<em><u>Recall:</u></em>
- A segment that divides an angle into equal parts is known as an angle bisector.
- Two triangles are congruent by the ASA Congruence Theorem if they share a common side and have two pairs of congruent angles.
In the diagram given, Angle bisector, GE, divides ∠HEF into congruent angles, ∠HEG ≅ ∠GEF.
Also divides ∠FGH into congruent angles, ∠HGE ≅ ∠FGE.
Both triangles also share a common side, GE
<em>This implies that: ΔHGE and ΔFGE have:</em>
two pairs of congruent angles - ∠HEG ≅ ∠GEF and ∠HGE ≅ ∠FGE
a shared side - GE
Therefore, ΔHGE and ΔFGE are congruent by the Angle-Side-Angle Congruence Theorem (ASA).
Learn more about ASA Congruence Theorem on:
brainly.com/question/82493
