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2 years ago

The distance formula can be derived from the Pythagorean theorem. True False

Mathematics

1 answer:

netineya [11]2 years ago

8 0

Correct answer is A.

d(A,B) - distance between points $A(x_1,y_1),B(x_2,y_2)$

$d^2=(x_2-x_1)^2+(y_2-y_1)^2$

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Find the area (in square feet) of a rectangle that measures 17" × 3'10".

Kitty [74]

Answer:

65 feet and 2 inches

Step-by-step explanation:

to find the area of a rectangle you need to multiply length times width in this case 17" times 3'10". But first you must convert everything into the same form(in this case feet) so first you can convert everything to inches by multiplying 3 times 12 which gives you 36 then add the 10, so it is now 46 inches then multiply that by 17 and altogether it is 782 inches, then divide by 12 (to convert it back to feet) and the answer is 65.1666666667. After you can round and get 65 feet and 2 inches.

6 0

2 years ago

A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave

erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, $L$ = 120 cm

Its wavelength $\lambda_1$ = 480 cm

$\lambda_2$ = 160 cm and $\lambda_3$ = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

The fundamental wavelength of a pipe which is open at both ends is 2L.
The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ $4L=4(120)=480\ cm$

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒ $\lambda_2=\frac{4L}{3}$ ⇒ $\lambda_3=\frac{4L}{5}$

⇒ $\lambda_2=\frac{4(120)}{3}$ ⇒ $\lambda_3=\frac{4(120)}{5}$

⇒ $\lambda_2=\frac{480}{3}$ ⇒ $\lambda_3=\frac{480}{5}$

⇒ $\lambda_2=160\ cm$ ⇒ $\lambda_3=96\ cm$

So the pipe is open at one end and closed at one end .

6 0

3 years ago

1.Jenny and Nola are comaring their phones. The height of Jenny's phone is 4.25 inches, and the height of Nola's phone is 4.75 i

son4ous [18]

I do not know what to answer here can you repost this question and make it a little bit more clear as i am sure it is really confusing to everybody else as it stands right now<span />

3 0

2 years ago

Which of these equations are in slope-intercept form?

maxonik [38]

Answer:

y = mx + b

Step-by-step explanation:

6 0

2 years ago

Find the area of a rectangle with a width of x3 + 5x - 9 and a length of x2 + 8.

Drupady [299]

Answer:

A = x⁵ + 13x³ - 9x² + 40x - 72

Step-by-step explanation:

The formula for the area of a rectangle is length X width, or A = lw.

Substitute the equations for the sides into the formula:

A = lw

A = (x² + 8)(x³ + 5x - 9) <= use the distributive property

A = x⁵ + 5x³ -9x² + 8x³ + 40x - 72 <= collect like terms

A = x⁵ + 13x³ - 9x² + 40x - 72

4 0

2 years ago