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The solution to the system of equations is (-3.88, 0.66) and (3.04, 1.09)
<h3>How to determine the solution to the system of equations?</h3>The system of equations is given as:
x^2y + yx^2 = 20
1/x + 1/y = 5/4
Multiply through the equation 1/x + 1/y = 5/4 by 4xy
So, we have:
4x + 4y = 5xy
So, we have the following system of equations
4x + 4y = 5xy
x^2y + yx^2 = 20
Next, we plot the graph of the system of equations
4x + 4y = 5xy
x^2y + yx^2 = 20
See attachment for the graph of the system
From the attached system, we have the point of intersection to be
(x, y) = (-3.88, 0.66) and (3.04, 1.09)
Hence, the solution to the system of equations is (-3.88, 0.66) and (3.04, 1.09)
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To solve for x in terms of b, simply treat b as a number, and solve for x as usual: first of all, we expand the left hand side:
Subtract 10 from both sides:
Divide both sides by -2b:
This means that in particular, if we set , we have