4 years ago

How do I solve this problem w

1 answer:

8 0

You definitely know how to find the area of a rectangle ... length times width. Right ? Well, write down the area of each rectangle, and then add up the 4 areas (using + signs). Hint: Each little rectangle on the right has an area of x-squared, so the sum of just those two is 2x-squared.

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ON A RECENT MATH TEST MARY SCORED 14 OF 16 CORRECT. JOHN SCORED 23 OF 26AND JOE SCORED 9 OF 11 CORRECT. WHO ACHIEVED THE HIGHER

Andrej [43]

Answer:

I think the answer is mary

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3 years ago

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What is value of the expression -2r/5s if r = -1/4 and s = 4/5?

Tanzania [10]

I don't know if this is right but 0.125

3 0

3 years ago

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-3x+6y= -3 and -5+y=-23

Ira Lisetskai [31]

-5 +y = -23

add 5 to each side

y = -18

-3x+6y = -3

-3x + 6(-18) = -3

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3 years ago

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Sum of 2x 2 + 3x - 4, 8 - 3x, and -5x 2 + 2.

Salsk061 [2.6K]

(2x²<span> + 3x - 4) + (8 - 3x) + (-5x</span>²<span> + 2)

= </span> 2x² + 3x - 4 + 8 - 3x - 5x² + 2

= -3x² + 6

= 3(-x² + 2)

5 0

3 years ago

PLEASE HELP

postnew [5]

Answer:

Below

Step-by-step explanation:

Substituting the given values:

f(6) = 6(2/3) - 2 = cube root of 6^2 - 2 = cube root 36 - 2

f(-6)= (-6)(2/3) - 2 = cube root of(-6)^2 - 2 = cube root 36 - 2

So This is true,

f(6) = cube root of 6^2 - 2 = cube root 36 - 2 = 1.3019

2 * f(3) = 2 * (cube root of 3^2 - 2 ) = 2 * (cube root of 9 - 2) = 0.1602

So False,

4 0

3 years ago