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Assoli18 [71]
3 years ago
5

A ballpark snack bar sold hot dogs and hamburgers. There were 9 times as many hot dogs sold as hamburgers during the third innin

g, for a total of 72 hot dogs sold. How many hamburgers were sold?
A.
9
B.
54
C.
8
D.
63
Mathematics
2 answers:
Delvig [45]3 years ago
7 0

Answer:

c.8

Step-by-step explanation:

vlabodo [156]3 years ago
7 0

Answer:

63

Step-by-step explanation:

i got 63 as my answer let me re check

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Step-by-step explanation:

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Find the average value fave of the function f on the given interval. f() = 5 sec2(/6), 0, 3 2
Inessa05 [86]

Answer:

f_{ave} = {\frac{10 }{3\pi }

Step-by-step explanation:

To find - Find the average value fave of the function f on the given interval. f(x) = 5 sec²(x/6), [0, 3\pi/2]

Proof -

We know that,

Average value of f in the interval [a, b] is -

f_{ave} = \frac{1}{b - a}\int\limits^b_a {f(x)} \, dx

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Here a = 0, b = \frac{3\pi }{2}, f(x) = 5sec^{2}(\frac{x}{6} )

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f_{ave} = \frac{1}{\frac{3\pi }{2}  - 0}\int\limits^{\frac{3\pi }{2} }_0 {5sec^2 ({\frac{x}{6} }) } \, dx

      = {\frac{2 }{3\pi }}\int\limits^{\frac{3\pi }{2} }_0 {5sec^2 ({\frac{x}{6} }) } \, dx

      = {\frac{10 }{3\pi }}\int\limits^{\frac{3\pi }{2} }_0 {sec^2 ({\frac{x}{6} }) } \, dx

      = {\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) }|^{\frac{3\pi }{2} }_0 \, ]

      = {\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) - tan({0) } \, ]

      = {\frac{10 }{3\pi }}[ {1 - 0 }  ]

      = {\frac{10 }{3\pi }

⇒f_{ave} = {\frac{10 }{3\pi }

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