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lara31 [8.8K]
3 years ago
13

Line CD passes through points (0, 2) and (4, 6). Which equation represents líne CD?

Mathematics
1 answer:
ladessa [460]3 years ago
8 0

the equation for a line is y = m x  + b

using the first set of coordinates (0,2)

2 = m * 0 + b

b = 2

using the second set of coordinates (4,6)

6 = 4 m + 2

4 m = 4

m = 4 / 4

m = 1

use those numbers into the line equation

y = x +2

Answer is: C

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Answer:

35

Step-by-step explanation:

A quadratic sequence is a form. of mathematical progression of numbers in which the subsequent differences between each consecutive term differ by the exact amount. This is known as the common second difference.

Hence in this case,

we have

S= 3+8+15+24+…..+Tn - 1.

S=. 3+8+15+……………..Tn-1 + Tn

Deducting 2nd series from the first

We have 0=3+5+7+…….Tn

Hence, we have Tn= n (n+2)

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Answer:

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Is the following function even, odd or neither? f(x)=x^3 +4x
erica [24]

Answer:

D, neither

Step-by-step explanation:

to determine whether a function is even, odd or neither, we need to know what it means

an even function is symmetric with respect to the y-axis

an odd function is symmetric with respect to the origin

to solve an equation to see if its even or odd, we would need to substitute <em>x</em> in the equation for <em>-x</em>.

in an even function when we substitute f(-x), it should be equal to to f(x)

in an odd function when we substitute f(-x), it should be equal to -f(x)

so lets test the function given to see if its even

f(x) = x³ + 4x

f(-x) = (-x)³ + 4(-x)

f(-x) = x³ - 4x

f(-x) = x³ - 4x ≠ f(x) = x³ + 4x

comparing this to the orignal function, we see that f(-x) = x³ - 4x is not even as we did not get the same output as the original function

now we should test to see if its odd. we have already seen what f(-x) is, now lets try -f(x) and compare it to f(-x) and f(x)

-f(x) = -(x³ + 4x) -->

-f(x) = -x³ - 4x ≠ f(-x) = x³ - 4x

f(-x) = x³ - 4x ≠ f(x) = x³ + 4x

comparing this to f(x) and f(-x), we see that it not odd as we did not get the same output

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Answer:

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