Answer: I got 50x+$75 but I’m not too sure for the last step
Step-by-step explanation:
Answer:
Step-by-step explanation:
You are going to integrate the following function:
(1)
furthermore, you know that:
lets call to this integral, the integral Io.
for a general form of I you have In:
furthermore you use the fact that:
by using this last expression in an iterative way you obtain the following:
(2)
with n=2s a even number
for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:
The given equation of the ellipse is x^2
+ y^2 = 2 x + 2 y
At tangent line, the point is horizontal with the x-axis
therefore slope = dy / dx = 0
<span>So we have to take the 1st derivative of the equation
then equate dy / dx to zero.</span>
x^2 + y^2 = 2 x + 2 y
x^2 – 2 x = 2 y – y^2
(2x – 2) dx = (2 – 2y) dy
(2x – 2) / (2 – 2y) = 0
2x – 2 = 0
x = 1
To find for y, we go back to the original equation then substitute
the value of x.
x^2 + y^2 = 2 x + 2 y
1^2 + y^2 = 2 * 1 + 2 y
y^2 – 2y + 1 – 2 = 0
y^2 – 2y – 1 = 0
Finding the roots using the quadratic formula:
y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1
y = 1 ± 2.828
y = -1.828 , 3.828
<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828)
and (1, 3.828).</span>
Answer:
Step-by-step explanation:
( B ) . No; the input value x = - 5 pairs with two output values.
