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Bumek [7]
3 years ago
14

A grocery store purchases melons from two distributors, J & K. Distributor J provides melons from organic farms. The distrib

ution of the diameters of the melons from distributor J is approximately normal with mean with 133 millimeters and standard deviation 5 mm. For a melon selected at random from distributor J, what is the probability that the melon will have a diameter greater than 137mm?
Mathematics
2 answers:
harina [27]3 years ago
6 0

Answer: green.                

Step-by-step explanation:

Vsevolod [243]3 years ago
3 0

Answer: 0.2119

Step-by-step explanation:

Find the z-score.

(x - μ)/σ

The equation would be:

(137-133)/5 = 0.8

p-value = 0.7881

Subtract that from 1.

1 - 0.7881 = 0.2119

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lawyer [7]

Answer:

21/4 or 5.25

Step-by-step explanation:

3 0
3 years ago
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What is the remainder when (x3 + 1) is divided by (x2 – x + 1)? x + 1 x 2 0
mariarad [96]

Answer:

x+1

Step-by-step explanation:

3 0
3 years ago
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PLEASE HELP ALGEBRA 2
svet-max [94.6K]


1) I use an interest program on my calculator. You could also use the equation listed in the math textbook. Principle=2500  Rate=0.025   Years=3 No.compounds/yr=4   Answer is $2,694.08

2) All positives

3) Square root of 343

4) Square root of 48

I hope that helps. :)

4 0
3 years ago
If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)​
Dahasolnce [82]

Answer:  195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

=(8/15+1)/(1-cosα)= 23/(15*(1-cosα))    (1)

As known cos²α=1-sin²α   (divide by cos²α both sides of equation)

cos²a/cos²α=1/cos²α-sin²α/cos²α

1=1/cos²α-tg²α

1/cos²α=1+tg²α

cos²α=1/(1+tg²α)

cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=

=+-sqrt(225/289)=+-15/17   (2)

Substitute in (1) cosα  by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0
3 years ago
Mika bought 9 rolls of film to take 180 pictures on a field trip. Some rolls had 36 exposures and the rest had 12 exposures. How
Juli2301 [7.4K]

The number of each type Mika bought =x = 6.8 rolls; y= 2.2 rolls.

<h3>Calculation using ratio</h3>

The number of rolls of film Mika  bought =  9 rolls

The number of rolls that had 36 exposures = x

The number of rolls that had 12 exposures = y

The total number of exposures = 36 + 12 = 48

To find the exposure by one roll = 48/9 = 5.3

If one roll = 5.3 exposure

    x roll    = 36 exposure

Make x roll the subject of formula,

x roll = 36/5.3 = 6.8 rolls

  • If one roll = 5.3 exposure

    y roll    = 12 exposure

Make y roll the subject of formula,

y = 12/5.3 = 2.2 rolls

Therefore, the number of each type Mika bought = x = 6.8 rolls; y= 2.2 rolls.

Learn more about ratios here:

brainly.com/question/2328454

#SPJ1

6 0
2 years ago
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