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Darya [45]
3 years ago
7

8. Let f(x) = 3x + 2 and g(x) = x - 3. Find f(x) - g(x) and state its domain.

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0
F(x) - g(x)
becomes
(3x + 2) - (x - 3)

which is
3x + 2 - x + 3

then add like terms
2x + 5

so f(x) - g(x) = 2x + 5
and it's domain should be all real numbers
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Find the 59th term of the following arithmetic sequence. 15, 23, 31, 39
m_a_m_a [10]

15~~,~~\stackrel{15+8}{23}~~,~~\stackrel{23+8}{31}~~,~~\stackrel{31+8}{39}~~,~~...~\hspace{10em}\stackrel{common~difference}{d=8} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\stackrel{\textit{term position}}{59}\\ a_1=\stackrel{\textit{first term}}{15}\\ d=\stackrel{\textit{common difference}}{8} \end{cases} \\\\\\ a_{59}=15+(59-1)8\implies a_{59}=15+472-8\implies a_{59}=479

4 0
3 years ago
Please help asap will mark brainliest
steposvetlana [31]
The answer is -6x^2 + 7x, or answer choice A.
6 0
4 years ago
Read 2 more answers
Herbert has sold 99, 37, 86, and 73 copeirs in the last 4 months, respectivly. How many copiers will he need to sell this month
jolli1 [7]

Answer:

Therefore 80 ceperies will he need to sell this month.

Step-by-step explanation:

Average: Average is the ratio of sum of all numbers to the total number present in the data.

Given that Herbert has sold 99, 37, 86 and 73 copeirs in the last 4 months.

Let he need to sell x copeirs in this month.

According to the problem,

\frac{99+37+86+73+x}{5}=75

⇒ 99+37+86+73+x= 75×5

⇒295 + x= 375

⇒x = 375 - 295

⇒ x= 80

Therefore 80 ceperies will he need to sell this month.

3 0
3 years ago
A segment with endpoints A(2,6) and C(5,9) is partitioned by a point B such that AB and BC form a 3:1 ratio. Find B​
Aneli [31]

Answer:

The coordinate of point B is (4, 8.25)

Step-by-step explanation:

Here, we want to find the coordinates of point B

To do this, we are to use the section internal division formula as follows;

(x,y) = (nx1 + mx2)/(m + n) , (ny1 + my2)/(m + n)

In this case;

(x1,y1) = (2,6)

(x2,y2) = (5,9)

(m,n) = (3,1)

Substituting these values into the section formula, we have;

(x,y) = (1(1) + 3(5))/(1 + 3) , (1(6) + 3(9))/3 + 1)

(x,y) = (16/4, 33/4)

(x,y) = (4,8.25)

3 0
3 years ago
An equation for <br> (-6,-3) (6,5)
Delvig [45]
Y= 2/3x+1
or
y=2/3x+b
.....................
6 0
3 years ago
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