Rate (R) = 25/3Interest = Rs. 350(d) Principal = Rs. 2400Find the time (t)
1 answer:
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Answer:
The amount of calories Lucie will burn by jumping for 1 minute is 8 calories
Step-by-step explanation:
The given data values are;
Minutes Calories Burned
40 320
80 640
120 960
160 1280
The value of calories burnt and the number of minutes of jump robe are seen to be directly proportional, such that we have;
40 minutes of jump rope will yield 320 calories burnt
Therefore we have;
1 minute of jump rope will yield 320/40 = 8 calories burnt
The amount of calories Lucie will burn by jumping for 1 minute = 8 calories.
Answer:
Slope(gradient)=
Good luck!
Intelligent Muslim,
From Uzbekistan.
Let h = height of the box,
x = side length of the base.
Volume of the box is
.
So
Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is
The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.
![4x = \frac{460}{ x^{2} } \\ 4x^{3} = 460 \\ x^{3} = 115 \\ x = \sqrt[3]{115} = 4.86](https://tex.z-dn.net/?f=%204x%20%3D%20%5Cfrac%7B460%7D%7B%20x%5E%7B2%7D%20%7D%20%20%5C%5C%20%204x%5E%7B3%7D%20%3D%20460%20%20%5C%5C%20x%5E%7B3%7D%20%3D%20115%20%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B115%7D%20%3D%204.86%20)
Then
So the box is 4.86 in. wide and 4.87 in. high.
x = side length of the base.
Volume of the box is
So
Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is
The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.
Then
So the box is 4.86 in. wide and 4.87 in. high.