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3 years ago

Finding zeros of a quadratic function

Mathematics

2 answers:

antoniya [11.8K]3 years ago

8 0

Answer:

-2, and 3

Step-by-step explanation:

-x² +x +6 = 0 is the same as

x²-x-6=0

but, x² -Sx+P=0

think what 2 numbers have the sum =1 and product = -6 that will be -2 and 3 witchh are your zeros

or you can use the graph or quadratic formula to solve

Nataly [62]3 years ago

8 0

F(x)=-x^2+x+6

Step-by-step explanation:

You might be interested in

Are the two parabolas defined below similar or congruent or both? Justify your reasoning. Parabola 1: The parabola with a focus

Dominik [7]

Answer:

They are similar by a factor of 14

Step-by-step explanation:

From the general equation of a parabola opening up (since the directrix is on the y axis and the focus is upwards this line) the focus coordinates are:

$Focus = (h,k+p) = (0,2)$

So h=0 and k+p=2, for the directrix:

$y = k-p=-4$

solving k and p from the two equations above:

$k=-1 and p=3$

So for Parabola 1 the equation would be:

$x^{2} =4*3(y+1)$

For Parabola 2 the general equation is:

$x^{2} =4*(3/2)(y)$

here h=0, k=0, p=3/2 so focus is (0,3/2), directix is y=-3/2, they have the same orientation.

they are not congruent. For them to be similar it must comply:

$x_{1}=k x_{2}\\y_{1}=ky_{2} => (1/12)x_{1} ^{2} -1 = k(1/6)x_{2} ^{2}$

replacing $x_{1}$ and solving for k:

$(1/12)(kx_{2}) ^{2} -1 = k(1/6)x_{2} ^{2}\\ (1/12)k^{2} x_{2}^{2}-1 = k(1/6)x_{2} ^{2}\\k-12 = (12/6)=2\\k = 2+12=14\\$

They are similar by a factor of 14

8 0

3 years ago

3(x-3)

blsea [12.9K]

Answer:

Step-by-step explanation:

Alright! So, this might seem complicated at first, but in the end its just a bit of algebra. If we think of a triangle, adding all of the sides together creates the perimeter. This means that 3(x-3) + 4x-1 + 2x+5 = 49. After this we can simplify to 9x - 5 = 49, and 9x = 54. Since 54/9 = 6, this means that x = 6.

4 0

4 years ago

Help help help it is simple one

algol [13]

Answer:

$3^{ -x+3}$