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aleksklad [387]
4 years ago
7

Identify the 42nd term of an arithmetic sequence where a1 = −12 and a27 = 66

Mathematics
2 answers:
Citrus2011 [14]4 years ago
8 0
A1 = -12
a27= 66
the formula of a27 is "a1 + 26d"
so

a1+26d= 66
-12 +26d=66
26d=78
d=3

now, the formula of "a42=a1+41d"
a42= a1+41d
a42= -12 + 41*3
a42= 111
stich3 [128]4 years ago
7 0
The arithmetic formula is expressed as an = a1 + d *(n-1)where n is an integer. Substituting from the given a1 = -12 and a27 = 66, 66 = -12 + d *(27-1). hence  , d is equal to 3. a42 thus using the formula is equal to 111. The final answer to this problem is 111.
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