Answer:
The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92
The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.
The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.
Answer: the answer is on a calculator
Step-by-step explanation:
If your aboe to do that you can so anything
On Oct 11: 1INR=0.04976AED
Oct 27 1INR=0.05022AED
However It's Price was highest on Oct 9 when 1AED was equal to 20.2395 INR
Answer:
<M = 32 and <Y = 103
Step-by-step explanation:
1. Since triangle BCM is congruent to triangle ZYR, we know the corresponding parts of the triangles are congruent. Therefore, <Z = <B = 45. The sum of a triangle’s angles is 180, so <M = 180 - <B - <C = 180 - 45 - 103 = 32
2. This is the exact same diagram, so we can use the information we have collected in #1. Since corresponding parts of congruent triangles are congruent, <Y must be congruent to <C, which equals 103. Therefore, <Y = 103.
I hope this helps! :)
Given the equation:
Let's identify the type of polar graph for the equation.
To identify the type of polar graph, use the formula below to get the Cartesian form:
Thus, we have:
![(x^2+y^2)=3\sqrt[]{x^2+y^2}-5x](https://tex.z-dn.net/?f=%28x%5E2%2By%5E2%29%3D3%5Csqrt%5B%5D%7Bx%5E2%2By%5E2%7D-5x)
We have the graph of the equation below:
We can see the graph forms a Limacon with an inner loop.
Therefore, the type of polar graph for the given equation is a limacon with inner loop.
ANSWER:
