Eight-tenths gran of a chemical is put into each jar. How many jars can be filled with 192 grams of the chemical?

The P value indicates that the probability of a linear correlation coefficient that is at least as extreme is 0.3% which is not significant (at α = 0.05), so there is insufficient evidence to conclude that there is a linear correlation between weight and consumption. of highway fuel in cars.

Step-by-step explanation:

We have that the correlation coefficient shows the relationship between the weights and amounts of road fuel consumption of seven types of car, now the P value establishes the importance of this relationship. If the p-value is lower than a significance level (for example, 0.05), then the relationship is said to be significant, otherwise it would not be so, this case being 0.003 not significant.

The statement would be the following:

The P value indicates that the probability of a linear correlation coefficient that is at least as extreme is 0.3% which is not significant (at α = 0.05), so there is insufficient evidence to conclude that there is a linear correlation between weight and consumption. of highway fuel in cars.

5 0

3 years ago

Which expression is equivalent to (x superscript four-thirds baseline x superscript two-thirds Baseline ) superscript one-third

Andrei [34K]

<h3>The equivalent expression is:</h3>

$(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}$

Solution:

Given expression is:

$\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}}$

We have to find the equivalent expression

We can simplify the above expression using law of exponents

Use the following law of exponents:

$a^m \times a^n = a^{m+n}$

Therefore,

$\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^{\frac{4}{3}+\frac{2}{3}})^{\frac{1}{3}}\\\\Simplify\\\\\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^2)^\frac{1}{3}$