Answer:
P(Coin landing heads and blue marble is randomly selected) = 3/20.
Step-by-step explanation:
In this question, two events simultaneously take place. First, all the probabilities have to be identified. It is mentioned that the coin is a fair coin, therefore the probabilities of all the outcomes associated with the coin tossing will be equal. Therefore:
P(Coin landing heads) = 1/2.
P(Coin landing tails) = 1/2.
There are a total of 3 blue + 4 green + 3 red = 10 marbles in the bag. Therefore:
P(Selected marble is blue) = 3/10.
P(Selected marble is green) = 4/10.
P(Selected marble is red) = 3/10.
Assuming that both the events are independent, the probabilities of both the events can safely be multiplied. Therefore:
P(Coin landing heads and blue marble is randomly selected) = 1/2 * 3*10 = 3/20.
Therefore, the answer is 3/20!!!
Answer:
x<21.6
Step-by-step explanation:
You're welcome. :)
Answer:
We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

For this case we have that:

And we see that 
So then we can conclude that the two events given are not independent and have a relationship or dependence.
Step-by-step explanation:
For this case we can define the following events:
A= In a certain computer a memory failure
B= In a certain computer a hard disk failure
We have the probability for the two events given on this case:

We also know the probability that the memory and the hard drive fail simultaneously given by:

And we want to check if the two events are independent.
We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

For this case we have that:

And we see that 
So then we can conclude that the two events given are not independent and have a relationship or dependence.
You can solve this by using "similar triangles".
In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.
You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:

Substitute for the values of AC, BC, DF and EF:


To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.

Substitute for the values and solve:


We have the value x to be 5.5 units and y to be 6 units.