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ELEN [110]
3 years ago
6

Can someone please answer this question please help please answer it correctly and please show work please help I need it please

help

Mathematics
2 answers:
EastWind [94]3 years ago
4 0

Answer:

24. $21 × 3 = $63

$200 - $63 = $137

$137 ÷ 4 = $34.25

C. $34.25

25. 2.5 ÷ 2 = 1.25

1.25 × Pi = 3.92699081 ...

C. 4 feet

44a. Equation: $12.75 + $0.75(v) = t

44b. $12.75 + $0.75(v) = $105.75

<em>Subtract</em><em> </em><em>$</em><em>12.75</em><em> </em><em>from</em><em> </em><em>each</em><em> </em><em>side</em>

$0.75(v) = 93

<em>Divide</em><em> </em><em>each</em><em> </em><em>side</em><em> </em><em>by</em><em> </em><em>0.75</em>

<em> </em> v = 124

She rented 124 videos

mr_godi [17]3 years ago
3 0

Answer:

Step-by-step explanation:

24)

200= 3(21) + 4x

200= 63 +4x

-63   -63

137= 4x

divide each side by 4

34 = x

c

25)

.5(pi)= about 1.6

1.6(2.5)= 4

c

44)

equation-     T= 12.17+0.75v

105.75= 12.17 + .75v

-12.17    -12.17

93.58= .75v

divide each side by .75

answer 125

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You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then
gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is  d\theta_1  =(14.36p)^o

Step-by-step explanation:

From the question we are told that

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     The height of the tree is  h

      The distance from the base is  D

h is mathematically represented as

            h  = D tan \theta       Note : this evaluated using SOHCAHTOA i,e

                                               tan\theta  =  \frac{h}{D}

Generally for small angles the series approximation of  tan \theta \  is

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=>        \frac{dh}{h} =  \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta

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        \pm  p%

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=>    \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta  = \pm p

=>      d\theta  =  \pm  \frac{\theta +  \frac{\theta^3}{3} }{1+ \theta ^2} *    \ p

 So  for   \theta_1

            d\theta_1  =  \pm  \frac{\theta_1 +  \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} *    \ p

substituting values  

          d [\frac{\pi}{12} ]  =  \pm  \frac{[\frac{\pi}{12} ] +  \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} *    \ p

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Converting to degree

           d\theta_1  = (0.25* 57.29) p

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