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evablogger [386]
3 years ago
11

Evaluate for d = 2. 2(d + 4d)

Mathematics
2 answers:
Lunna [17]3 years ago
8 0

Answer: d = 12

2(2 + 4d)

Disturbte the 2 time everything and you get

4 + 8D add alike variable and the answer is d=12

Sav [38]3 years ago
6 0

Substitute 2 for d.

2(d + 4d) \\ 2(2 + (4 \times 2)) \\ 2(2 + 8) \\ 2(10) \\ 20

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SpyIntel [72]

Answer:

28

Step-by-step explanation:

3 0
2 years ago
What is the simplified form of (3.25x10^3)(7.8x10^6) written in scientific notation?
BabaBlast [244]

Answer: 2.535*10^{10}


Step-by-step explanation:

1. By definition, scientific notation has the following form:

a*10^{b}

Where:

<em> a</em> is a number between 1 and 10 but does not include 10.

<em> b </em>an integer.

2. When you multiply 3.25 by 7.8  the result is 25.35 and when you multiply 10^{3} by 10^{6}, you obtain 10^{9}, but to write ree thsult in scientific notation, the decimal point must be after the first digit. Therefore, you must move the decimal point one place to the left. So, the exponent changes from 9 to 10:

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3 0
2 years ago
Please help !! i need to know how to solve it.
Vera_Pavlovna [14]

We can determine the value of the adult ticket cost and student ticket cost by following these steps:

1. solve form one of the variables from one of the equations

Let's solve for a from 2a + 2s = 40

2a + 2s = 40

2a + 2s - 2s = 40 - 2s

2a = 40 - 2s

2a/2 = 40/2 - 2s/2

a = 20 - s

2. Replace the expression found and solve for s

4a + 5s = 87

4(20 - s) + 5s = 87

4×20 - 4×s + 5s = 87

80 - 4s + 5s = 87

80 + s = 87

80 - 80 + s = 87 - 80

s = 7

3. Replace 7 for s into a = 20 - s

a = 20 - 7

a = 13

Then, a = 13 and s = 7.

Then the adult ticket cost is $13 and the student ticket cost is $7

3 0
1 year ago
Right triangle EFG and right triangle EHG overlap as shown below. Angle HEG measures 35° and angle FGE measures 30°.
lesantik [10]

Given:

Triangle EFG and EHG are two right triangles.

m\angle HEG=35^\circ

m\angle FGE=30^\circ

To find:

The values of x and y.

Solution:

In triangle EFG,

m\angle EFG+m\angle FGE+m\angle FEG=180^\circ        [Angle sum property]

90^\circ+30^\circ+(x+35)^\circ=180^\circ

(x+155)^\circ=180^\circ

x+155=180

x=180-155

x=25

In triangle EHG,

m\angle EHG+m\angle HEG+m\angle EGH=180^\circ        [Angle sum property]

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3 0
3 years ago
There are 10 boys and 20 girls in Mrs Brook's class.
notsponge [240]

Answer:

Step-by-step explanation:

First let us consider how we calculate the mean test mark in the first place, we add up the individual test marks of the entire class to give the total test mark then we divide by the number of students. This means we need two pieces of information to calculate the boys' mean mark, the total boys' mark and the number of boys. We already know the number of boys but how do we work out the total boys' test mark? If we can work out the total class mark and total girls' mark we can find the total boys' mark by subtracting the total girls' mark from the total class mark. To do this we can work backwards to find the total mark for the whole class by taking the mean mark and multiplying it by the number of students, this gives us Total Class Mark = Mean Class Mark x Number of Students = 60 x 30 = 1800. We can do the same for the girls' mark giving us Total Girls' Mark = Mean Girls' Mark x Number of Girls = 54 x 20 = 1080. This then gives us the total boys mark as Total Boys' Mark = Total Class Mark - Total Girls' Mark = 1800 - 1080 = 720. Now we have everything we need to work out the boys' mean mark and we get Boys' Mean Mark = Total Boys' Mark/Number of Boys = 720/10 = 72.

4 0
3 years ago
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